模拟掷 6 面骰子并将每次掷骰的结果相加直到掷出 1 的 Python 程序

Question

所以这是我写的代码，试图回答标题中的问题:

import random
print("Well, hello there.")
while True:
    a = random.randint(1,6)
    sum = 0
    if(a==1): #If a one is indeed rolled, it just shows rolled a 1 and 'Pigs out' and makes the score equal to 0(player score that is) and is a sort of a GameOver
        print("Pigged out!")
        break #To get out of the loop
    else:
        while(sum<=20): 
            sum += a
            print(sum)

程序应保持分数直到达到 20(或更多)并显示它。它本质上代表了“ pig ”的单转。我无法弄清楚我哪里出了问题？任何建议都会有所帮助。

示例输出示例:

-掷出 6
-掷出 6
-掷出 5
-掷出 6
- 回合得分为 23

Answer 1

如果我理解正确，那么你可以简化很多，像这样:

import random
print("Well, hello there.")
score = 0
while score < 20:
    a = random.randint(1,6)
    print("A {} was rolled".format(a))
    score += a
    if a == 1:
        print("Pigged out!")
        score = 0
        break
print("Turn score is {}".format(score))