java - 重新创建特定的 JSON 结构

Question

我正在尝试在 JAVA 中重新创建以下 JSON。

[{                  
"Operation": {
    Product: "MyProduct",
    Noun: "MyNoun",
    Verb: "MyVerb"
},
"Authentication": {
    UserID: "UserName",
    Password: "Password"
}}]

我觉得 Maps 是正确的选择。但是我无法形成正确的结构。

Map<String,String> opsDictionary =  new HashMap<String,String>();
    opsDictionary.put("Product","MyProduct");
    opsDictionary.put("Noun","MyNoun");
    opsDictionary.put("Verb", "MyVerb");

Map<String,String> authDictionary =  new HashMap<String,String>();
    authDictionary.put("UserID","UserName");
    authDictionary.put("Password", "Password");


JSONObject postdata = new JSONObject();
postdata.put("Operation", opsDictionary);
postdata.put("Authentication", authDictionary);

吐出这个不正确版本:

{
    "Authentication": "{UserID=CADEMO, Password=TESTPASSORD}",
    "Operation": "{Noun=User, Product=TOPSInventory, Verb=Authenticate}"
}

我玩弄了将 map 打包成一个包的想法

Bundle dataBundle = new Bundle();
dataBundle.putStringArray("Operation", opsDictionary);
dataBundle.putStringArray("Authentication", authDictionary);

我做错了什么？

我能够使用词典在我的 iOS 版本中复制这种格式。

 NSMutableDictionary * dicOperation = [[NSMutableDictionary alloc]init];
    [dicOperation setValue:product forKey:@"Product"];
    [dicOperation setValue:noun    forKey:@"Noun"];
    [dicOperation setValue:verb    forKey:@"Verb"];

    NSMutableDictionary * dicAuthentication = [[NSMutableDictionary alloc] init];
    [dicAuthentication setValue:username   forKey:@"UserID"];
    [dicAuthentication setValue:password forKey:@"Password"];


    NSData* jsonData = [NSJSONSerialization dataWithJSONObject:dictPackage options:NSJSONWritingPrettyPrinted error:&error];

我希望有适用于 Android 的类似解决方案。

Answer 1

您不需要使用 Hashmap。这可能是导致字符串连接结果的原因。

应该是这个

JSONObject opsDictionary = new JSONObject();
    opsDictionary.put("Product","MyProduct");
    opsDictionary.put("Noun","MyNoun");
    opsDictionary.put("Verb", "MyVerb");


JSONObject authDictionary = new JSONObject(); 
    authDictionary.put("UserID","UserName");
    authDictionary.put("Password", "Password");


JSONObject postdata = new JSONObject();
postdata.put("Operation", opsDictionary);
postdata.put("Authentication", authDictionary);

如果您打算创建一个数组，最后附加到一个数组(在循环中或根据需要):

JSONArray ja = new JSONArray();
ja.put(postdata );

来自 How to create correct JsonArray in Java using JSONObject 的代码用法