javascript - 如何在不使用三个嵌套 for 循环的情况下解决这个问题

Question

我有一个类似这样的对象数组

var data = [{"2017-09-13":{date_time:"2017-09-13",value:"20"}},{"2017-09-13":{date_time:"2017-09-13",value:"22"}},{"2017-09-15":{date_time:"2017-09-15",value:"25"}},{"2017-09-15":{date_time:"2017-09-15",value:"30"}},{"2017-09-16":{date_time:"2017-09-16",value:"10"}}];

我有一个像这样的日期数组

var dates = ["2017-09-13","2017-09-15"];

我想修改数据数组，使其仅包含日期数组中提到的日期。我尝试过这样的事情

var date = [];
for (var i = 0; i < data.length; i++) {
        for (var j = 0; j < dates.length; j++) {
            for (key in data[i]) {
                if (dates[j] == key) {
                    date.push(data[i])
                }
            }
    }
}

它给了我所需的结果。然而，这效率不高并且滞后于应用程序。有什么有效的方法吗？

编辑:更新了正确的数据结构

Answer 1

const data = [
    {
        "2017-09-13": {
            "date_time": "2017-09-13",
            "value": "20"
        }
    },
    {
        "2017-09-13": {
            "date_time": "2017-09-13",
            "value": "22"
        }
    },
    {
        "2017-09-15": {
            "date_time": "2017-09-15",
            "value": "25"
        }
    },
    {
        "2017-09-15": {
            "date_time": "2017-09-15",
            "value": "30"
        }
    },
    {
        "2017-09-16": {
            "date_time": "2017-09-16",
            "value": "10"
        }
    }
];

const dates = ["2017-09-13", "2017-09-15"];
const datesSet = new Set(dates);

const filteredData = data.filter(item => datesSet.has(Object.keys(item)[0]));
console.log(filteredData);

考虑删除使用日期作为键，因为它们似乎是冗余信息:

const data = [
    {
        "date_time": "2017-09-13",
        "value": "20"
    },
    {
        "date_time": "2017-09-13",
        "value": "22"
    },
    {
        "date_time": "2017-09-15",
        "value": "25"
    },
    {
        "date_time": "2017-09-15",
        "value": "30"
    },
    {
        "date_time": "2017-09-16",
        "value": "10"
    }
];

const dates = ["2017-09-13", "2017-09-15"];
const datesSet = new Set(dates);

const filteredData = data.filter(item => datesSet.has(item.date_time));
console.log(filteredData);