python - 绘制阶梯直方图而不用底线闭合多边形

Question

如何删除关闭阶梯直方图路径的底线？

import numpy as np
import matplotlib.pyplot as plt

mu, sigma = 100, 15
x = mu + sigma * np.random.randn(10000)
fig = plt.figure()
ax = fig.add_subplot(111)
n, bins, patches = ax.hist(x, 50, normed=1, histtype='step')
plt.ylim(-.005, plt.ylim()[1])
plt.show()

更新:已报告并已修复:

https://github.com/matplotlib/matplotlib/pull/2113

Answer 1

最简单的方法是自己绘制:

import numpy as np
import matplotlib.pyplot as plt

mu, sigma = 100, 15
x = mu + sigma * np.random.randn(10000)
fig = plt.figure()
ax = fig.add_subplot(111)
bins, edges = np.histogram(x, 50, normed=1)
ax.step(edges[:-1], bins, where='post')
plt.ylim(-.005, plt.ylim()[1])
plt.show()

参见 doc或 Step function in matplotlib理解where=post。您需要切掉边缘的最后一个条目，因为直方图返回 [left_edege_0, left_edge_1, ..., left_edge_(n-1), right_edge_(n-1)](请参阅 doc )

这已被视为回归，并将至少在 1.3 中得到修复。相关公关:https://github.com/matplotlib/matplotlib/pull/2113