Python - 使用 Numpy 的多个矩阵的元素方式

Question

我正在实现一个滑动窗口模型，我想在其中初始化一个矩阵 @t 作为前 N 个矩阵的逐元素均值，其中 N 是窗口大小。这是我最初的尝试，它显示了最后 N 个矩阵:

list_of_arrays = [np.array([]) for i in range(3)]
N=2 # window size
# past 3 matrices
list_of_arrays[0] = np.array([[0.1,0.2],[0.3,0.4]])
list_of_arrays[1] = np.array([[0.5,0.6],[0.7,0.8]])
list_of_arrays[2] = np.array([[0.9,1.0],[1.1,1.2]])

# at t=3, get element-wise means of previous N matrices
t=3
range1 = lambda start, end: range(start, end+1) # modified range function
answer = [list_of_arrays[t-j] for j in range1(1,N)]

所需的答案是过去 N 个矩阵的逐元素均值。对于上面的系列，它是:

(list_of_arrays[2]+list_of_arrays[1])/2 = [[0.7,0.8],[0.9,1.0]]

我应该如何修改 answer 行上的列表理解以获得所需的答案？

Answer 1

我想通了。这是对问题中指示的 answer 行的必要修改:

answer = np.mean([list_of_arrays[t-j] for j in range1(1,N)], axis = 0)
>> array([[ 0.7,  0.8],
>>        [ 0.9,  1. ]])