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javascript - 显示 0 条数据表

转载 作者:行者123 更新时间:2023-11-28 17:40:26 24 4
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我在数据表中遇到问题。为什么我得到一个“显示 0 到 0 个条目”,也无法搜索,它总是显示“没有可用数据”并且分页被禁用。我该怎么办?

这是我的代码:

//Show Products Table
function show_products() {
var action = "Show Products";
$.ajax ({
type: 'POST',
url: '../admin/class.php',
data: {action: action},
success: function(data) {
//if success it will display the data
$('#show_products').html(data);
}
});
}

//class.php(data)
if(isset($_POST['action']) && !empty($_POST['action'])) {
$action = $_POST['action'];
switch($action) {
case 'Show Products':
//call the function show_products();
show_products();
break;
}
}

//Function to fetch the all products
function show_products() {
GLOBAL $db_conn;
$search_query="SELECT p.product_id as productID, p.*, pe.* FROM tblproduct p JOIN (SELECT p.product_id, MIN(pe.product_extension_id) AS product_extension_id FROM tblproduct p LEFT JOIN tblproduct_extension pe ON pe.product_id = p.product_id GROUP BY product_id ORDER BY product_id) product_unique LEFT JOIN tblproduct_extension pe ON pe.product_extension_id = product_unique.product_extension_id WHERE p.product_id =product_unique.product_id";
$query = mysqli_query($db_conn, $search_query);

while($row = mysqli_fetch_array($query)) {
$status = ($row['product_stocks'] == 0) ? '<label class="label label-danger">Out of stocks</label>' : '<label class="label label-success">In stocks</label>';
?>
<tr>
<td><?=$row['product_name']?></td> /*fetch product_name*/
<td><?=$row['product_brand']?></td> /*fetch product_brand*/
<td><?=$row['category_name']?></td> /*fetch category_name*/
<td>&#8369;<?=number_format($row['product_price'], 2)?></td> /*product_price*/
<td><?=$row['product_size']?></td> /*fetch product_size*/
<td><?=$row['product_stocks']?></td> /*fetch product_stocks*/
<td><?=$status?></td> /*display status if 0 stocks "outofstock"*/
</tr>
<?php
}
}

//Script of datatable
$(document).ready(function(){
//get the id of table
$('#datatable1').DataTable();
});

屏幕截图:

datatable

PS:我包含了所有库。

最佳答案

仅在从服务器检索数据后初始化表。

$.ajax ({
type: 'POST',
url: '../admin/class.php',
data: {action: action},
success: function(data) {
// If table is initialized
if ($.fn.DataTable.isDataTable('#datatable1')){
// Destroy existing table
$('#datatable1').DataTable().destroy();
);

//if success it will display the data
$('#show_products').html(data);

// Initialize the table
$('#datatable1').DataTable();
}
});

如果您将多次发出 Ajax 请求。

关于javascript - 显示 0 条数据表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48061576/

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