iphone - 问在xcode4中使用json

Question

你好，我是 iPhone 开发新手我想在 xcode4 中显示带有 json 的选择数组到 mysql我在 php 中输出 json 代码 是这样的:

{"data":[{"id":"16","nama":"yes","desk":"test2","gambar":""}]}

我的代码模块是这样的:

list.m

- (void)viewDidLoad
{
    AIR = [[NSMutableArray alloc] init];

    NSURL *url = [NSURL URLWithString:@"http://192.168.0.169/demo/json/rifle.php"];

    NSString *jsonreturn = [[NSString alloc] initWithContentsOfURL:url];
    NSLog(jsonreturn);

    NSData *jsonData =[jsonreturn dataUsingEncoding:NSUTF8StringEncoding];
    NSError *error =nil;

    NSDictionary *dict =[[CJSONDeserializer deserializer]deserializeAsDictionary:jsonData error:&error];
    if (dict) {
        AIR = [[dict objectForKey:@"data"] retain];
    }
    NSLog(@"Array:%@",AIR);
}


#pragma mark - Table view data source

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
    // Return the number of sections.
    return 1;
}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
    // Return the number of rows in the section.
    return [AIR count];
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"Cell";

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
    if (cell == nil) {
        cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier] autorelease];
    }

    // Configure the cell...
    NSDictionary *dict = [AIR objectAtIndex:indexPath.row];

    // deklarasi image ambil file gambar didalam field nama
    cell.textLabel.text = [dict objectForKey:@"nama"];

    // deklarasi image ambil file gambar didalam field desk
    cell.detailTextLabel.text = [dict objectForKey:@"desk"];

    // deklarasi image ambil file gambar didalam field gambar
    UIImage *cellImage =[UIImage imageNamed:[dict objectForKey:@"gambar"]];
    cell.imageView.image = cellImage;


    return cell;
}

#pragma mark - Table view delegate

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    subway *mAIR = [[subway alloc] initWithNibName:@"subway" bundle:nil];
    [mAIR setTitle:@"AIRGUN DESC DETAIL"];
    [self.navigationController pushViewController:mAIR animated:YES];
    [mAIR release];
}

subway 是另一个带有 tableView iniNibName subway n 的 ViewController 现在我的问题是如何为选择数组获取 $id(参见 json 代码)如果在 php 中像这样评论

SELECT * FROM data where id="$id"

所以如果我选择列表 NIB，它们将在地铁 NIB 中显示输出

请帮帮我

谢谢

Answer 1

我也这样做，我使用 SBJSON 库:

https://github.com/stig/json-framework/

• DownloadedData 是您从网络服务收到的 JSON

• parsedData 是 JSON 解析后的 NSDicitonary

  NSString *responseString = [[NSString alloc] initWithData:downloadedData encoding:NSUTF8StringEncoding];    
  
  SBJSON *parser = [SBJSON new];
  
  NSDictionary *parsedData = (NSDictionary *)[parser objectWithString:responseString error: nil];
  [responseString release];
  
  
  [parser release];
  

您可以在此处找到教程: http://blog.zachwaugh.com/post/309924609/how-to-use-json-in-cocoaobjective-c