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javascript - 无法得到 jquery parentsUntil 工作

转载 作者:行者123 更新时间:2023-11-28 17:26:56 25 4
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我一直在尝试使用 jquery parentsUntil 方法来隐藏按钮,直到选中一个单选框,但我似乎无法让它工作。这可能是显而易见的事情,但它已经困扰了我几天了。任何人都可以看到我做错了什么。

 (function($) {
$(function(){
$('.last-item').change(function() {
if( $(this).val() != '' ) {
$(this).parentsUntil('.step').find('.button-next').removeClass('hide');
$(this).parentsUntil('.step').find('.button-next').addClass('show');
console.log("changing the last item");
}

});

});
})(jQuery);
.hide {
display: none;
}

.show {
display: block !important;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<div class="step">
<h1>Step 3 - Personal</h1>
<div class="input-wrapper radio no-feedback">
<div class="row no-gutter content-position-outer">
<div class="col-md-6 content-center-inner">
<label for="gender">What gender are you? <sup>*</sup></label>
</div>
<div class="col-md-6 content-center-inner">
<div class="row">
<div class="col-md-5 col-md-offset-2">
<label class="radio-sex" for="gender_male">
<input class="sr-only last-item" type="radio" placeholder="Male" name="gender" value="Male" id="gender_male" required="required" />
<div class="radio-img radio-img-sex-male"></div>
Male
</label>
</div>
<div class="col-md-5">
<label class="radio-sex" for="gender_female">
<input class="sr-only last-item" type="radio" placeholder="Female" name="gender" value="Female" id="gender_female" required="required" />
<div class="radio-img radio-img-sex-female"></div>
Female
</label>
</div>
</div>
</div>
</div>
</div>
<div class="row">
<div class="col-md-3">
<a href="" class="button-prev" data-progress="2" data-step="step-2">Previous</a>
</div>
<div class="col-md-3 col-md-push-6">
<a href="" class="button-next hide" data-progress="4" data-step="step-4">Next</a>
</div>
</div>
</div>

JS Fiddle

最佳答案

.parentsUntil()获取“当前匹配元素集中每个元素的祖先,直到但不包括选择器匹配的元素,”。

尝试 .closest()相反

关于javascript - 无法得到 jquery parentsUntil 工作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39318269/

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