javascript - 如何在 fs.readFile 和其他非导入路径中使用 Typescript 中的路径

Question

假设我有以下tsconfig.json

{
    "compilerOptions": {
            "baseUrl": "src", 
            "paths": {
                "app/*": ["src/*"],
            }
            ...
    }
}

And I have the following folder structure

    src/
       content/
           numbers.csv
       long/
           folder/
               path/
                  to/
                     file.ts

And now I want to use `fs.readFileSync` to read `numbers.csv`. But I don't want to do something like `fs.readFileSync(path.normalize(__dirname + '../../../../content/numbers.csv))`. I rather do something like `fs.readFileSync('app/content/numbers.csv')`.

Is this possible in Typescript?

Answer 1

我很确定，不可能根据您的目的编辑 tsconfig。

tsconfig.json文件用于将ts代码转(编译)为js代码，后面的(js代码)由nodejs执行。 paths 选项向 ts 编译器提供有关 ts 文件(等待编译)的信息，ts 编译器无法决定如何传输 fs.readFileSync(YOUR_PATH) 行。

您可以使用process.cwd()或其他方法来避免这么长的路径:

const appPath = process.cwd() + '/src/'; // if the script is always excuted in the src directory
// or
const appPath = 'YOUR/DATA/PATH'; // absolute path

fs.readFileSync(appPath + '/content/numbers.csv');