python - 包含至少三个连续元音的序列

Question

我正在尝试创建一个函数来评估是否至少连续包含三个元音。

到目前为止我已经尝试过:(我不知道如何评估它们是否连续)有什么想法吗？

def isConsecutive(word):
    # initialize vowel count
vCounter = 0
for letter in word:
    if letter == isVowel(word):  
        vCounter += 1
    else:
        vCounter = 0

    if vCounter < 3:    
        return False
return True

辅助函数

def isVowel(char):
    return len(char) == 1 and char.lower() in 'aeiou'

Answer 1

检查您是否按顺序到达了第三个vovel，应该在vCounter += 1 之后。如果有三个vovels:返回true。

此外，isVowel 检查应该应用于 letter，而不是整个 word。

def isVowel(char):
    return char.lower() in 'aeiou'

def isConsecutive(word):
    # initialize vowel count
    vCounter = 0
    for letter in word:
        if isVowel(letter): # <= check if the letter is a vowel
            vCounter += 1
            if vCounter >= 3: # <= do the check right here
                return True
        else:
            vCounter = 0

    return False # <= if we did not find three vovels in the loop, then there is none

print "hello: " + str(isConsecutive("hello"))
print "heeello: " + str(isConsecutive("heeello"))
print "hellooo: " + str(isConsecutive("hellooo"))

在线试一试: DEMO