javascript - 查找仅包含不同对象的数组

Question

这个问题已经有答案了:

Remove duplicate values from JS array [duplicate] (54 个回答)

已关闭 4 年前。

我有一个数组:

var objArray = [
   { id: 0, name: ‘Object 0’, otherProp: ‘321’ },
   { id: 1, name: ‘O1’, otherProp: ‘648’ },
   { id: 2, name: ‘Another Object’, otherProp: ‘850’ },
   { id: 3, name: ‘Almost There’, otherProp: ‘046’ },
   { id: 4, name: ‘Last Obj’, otherProp: ‘984’ },
   { id: 0, name: ‘Object 0’, otherProp: ‘321’ }
];

此处 id 0 添加两次。我只想要一个不具有相同对象的数组。

预期输出:

a = [
   { id: 0, name: ‘Object 0’, otherProp: ‘321’ },
   { id: 1, name: ‘O1’, otherProp: ‘648’ },
   { id: 2, name: ‘Another Object’, otherProp: ‘850’ },
   { id: 3, name: ‘Almost There’, otherProp: ‘046’ },
   { id: 4, name: ‘Last Obj’, otherProp: ‘984’ }] 

如何在 JavaScript 中执行此操作。

Answer 1

您可以通过在 Set 中查找 id 来过滤数组。

var array = [{ id: 0, name: 'Object 0', otherProp: '321' }, { id: 1, name: 'O1', otherProp: '648' }, { id: 2, name: 'Another Object', otherProp: '850' }, { id: 3, name: 'Almost There', otherProp: '046' }, { id: 4, name: 'Last Obj', otherProp: '984' }, { id: 0, name: 'Object 0', otherProp: '321' }],
    seen = new Set,
    result = array.filter(({ id }) => !seen.has(id) && seen.add(id));

console.log(result);