javascript - 火星探测器卡塔。可以转弯也可以前进

Question

我正在做这个 kata，其中我有一个漫游器，我需要能够向 10x10 板内发出指令。 Rover 一次只能进行 1 个 Action 。要么转身，要么前进。

当我console.log提前功能时，我没有得到漫游器在板上的更新位置。我想不通。我写了所有内容并找到了解决方案，但后来我破坏了它并覆盖了某些内容，并且无法弄清楚我删除或更改了什么。

// Rover Object Goes Here
// ======================
let grid;
let rover = {
  direction: "N",
  location: {x:0,y:0},
  // path: [{x:0,y:0}]
}

// ======================

//Turn left function
function turnLeft(rover){
  switch (rover.direction) {
    case "N":
      rover.direction = "W";
      break;
    case "W":
      rover.direction = "S";
      break;
    case "S":
      rover.direction = "E";
      break;
    case "E":
      rover.direction = "N";
      break; 
  }   
  console.log(`turnLeft was called!. Rover is now facing ${rover.direction}` );    
}


//Turn right function
function turnRight(rover){
  switch (rover.direction) {
    case "N":
      rover.direction = "E";
      break;
    case "E":
      rover.direction = "S";
      break;
    case "S":
      rover.direction = "W";
      break;
    case "W":
      rover.direction = "N";
      break;      
  }   
  console.log(`turnRight was called!. Rover is now facing ${rover.direction}` );    
}


//  Function for moving rover
function moveForward(theRover) {
  //Variables
  let locationX = theRover.location.x;
  let locationY = theRover.location.y;
  let roverDir = theRover.direction;
  let roverInfoConsole = `Current rover position is x:${locationX} y:${locationY}
                Current rover direction is ${roverDir} `; 
  // Restricted Moves  
  if ( (roverDir === "N" && locationY <= 0) ||
      (roverDir === "E" && locationX >= 9) ||
      (roverDir === "S" && locationY >= 9) ||
      (roverDir === "W" && locationX <= 0)     ) {

    console.log(`Cannot move in that direction. The rover would move to a restricted area.
                ${roverInfoConsole}`);

  //allowed moves
    //North
   } else if (roverDir === "N" && locationY <= 9) {
      locationY = locationY - 1;
      console.log(`moveForward was called. 
                   Current rover position is x:${locationX} y:${locationY}
                Current rover direction is ${roverDir} `);
    //East
   } else if (roverDir === "E" && locationX < 9) {
      locationX = locationX + 1;      
      console.log(`Current rover position is x:${locationX} y:${locationY}
                Current rover direction is ${roverDir} `);
    //South
   } else if (roverDir === "S" && locationY  < 9) {
      locationY = locationY + 1;
      console.log(`moveForward was called. 
                   Current rover position is x:${locationX} y:${locationY}
                Current rover direction is ${roverDir} `);
    //West
   } else if (roverDir === "W" && locationX < 9) {
      locationX = locationX - 1;      
      console.log(`moveForward was called. 
                   Current rover position is x:${locationX} y:${locationY}
                Current rover direction is ${roverDir} `);
   }
};

console.log(turnRight(rover));
console.log(moveForward(rover));
console.log(moveForward(rover));
console.log(turnRight(rover))
console.log(moveForward(rover));
console.log(moveForward(rover));

我预计最终的输出是:

"Current rover position is x:2 y:2
Current rover direction is S " 

但它没有更新位置。这是我实际得到的整个控制台日志:

"turnRight was called!. Rover is now facing E"
undefined
"Current rover position is x:1 y:0
                Current rover direction is E "
undefined
"Current rover position is x:1 y:0
                Current rover direction is E "
undefined
"turnRight was called!. Rover is now facing S"
undefined
"moveForward was called. 
                   Current rover position is x:0 y:1
                Current rover direction is S "
undefined
"moveForward was called. 
                   Current rover position is x:0 y:1
                Current rover direction is S "
undefined

Answer 1

我认为您必须递增/递减 theRover.location.x 和 theRover.location.y 而不是您正在使用的临时变量。