python - 在字典中计算大写或非大写

Question

所以我有这本字典，

word_counts = {'Two':2, 'one':3, 'Forks.':1, 'knife.':2, 
'glasses.':2, 'plate.':1, 'Naptkin.':1, 'his':2}

而且我需要计算有多少是大写的和非大写的。我知道我需要通过获取字典的键并循环遍历它们来做到这一点，但我遇到了麻烦。请帮忙。谢谢!

尝试将计数器变量与 for 循环以及 isupper() 和 islower() 一起使用，但它不起作用。如果您有更好的方法，请告诉我!

#What ive done so far
word_counts = {'Two':2, 'one':3, 'Forks.':1, 'knife.':2, 
    'glasses.':2, 'plate.':1, 'Naptkin.':1, 'his':2}

for word, occurence in words:
        upper_counter = 0
        lower_counter = 0
        for word in word_counts.items():
            if word.isupper():
                upper_counter += 1
            elif word_islower():
                lower_counter += 1

Answer 1

# The counters should be initialised before the loop
upper_counter = 0
lower_counter = 0

for word in word_counts:  # Looping over a dictionary gives the keys
    if word[0].isupper():  # Just have to check if the first character is upper case
        upper_counter += 1
    else:
        lower_counter += 1