javascript - 如何从数组 1 中删除项目并将项目推送到数组 2

Question

我尝试的是检查 state.newCardArray 并根据索引删除该项目，然后将其推送到 state.arrayFoldedCards。这是一个纸牌游戏，所以如果 newCardArray 为空并且没有赢家或输家，那么游戏就会停止......

const initialState = {
  newCardArray: ['a', 'b', 'c']; // after removing the array looks like ['a', 'c']
  arrayFoldedCards: [] // pushing to the array resulted in an updated array that looks like ['b']
}

export const game = (state = initialState, action) => {
  switch (action.type) {
    case types.GET_CARD:
      {
        const getRandomNumber = Math.floor(state.newCardArray.length * Math.random());
        console.log(state.newCardArray);
        console.log(state.arrayFoldedCards);
        return {
          ...state,
          randomNumber: getRandomNumber,
          arrayFoldedCards: state.newCardArray[getRandomNumber].push(state.arrayFoldedCards.pop())
        }
      }
  }
}

Answer 1

看起来你想要像 splice/concat 这样的东西

var idxToRemove = 1; //Removing 'b'
var arr0 = ['a', 'b', 'c']; 
var arr1 = []; //Array to move to

return arr1.concat(arr0.splice(idxToRemove, 1));

Splice 返回已删除元素的数组，以便您可以将它们连接在一起。 Concat 合并两个数组而不改变任何一个。