javascript - 如何从嵌套 JSON 有效负载 (JavaScript) 中删除特定元素？

Question

我想创建一个函数来检查嵌套 JSON 中的特定元素，如果找到，则删除该元素的所有实例，即使在数组中找到也是如此。

例如，假设我有一个 JSON:

{
    "userId": "John991",
    "group1": {
        "color": "red",
        "height": "100",
        "userid": "John992"
    },
    "data": [
        {
            "userid": "John993",
            "Key3": "Value3"
        },
        {
            "group2": [{
                "userid": "John994"
            }]
        }
    ],
    "Key1": "Value1",
    "Key2": "Value2"
}

我希望我的结果是

{
    "group1": {
        "color": "red",
        "height": "100"
    },
    "data": [
        {
            "Key3": "Value3"
        },
        {
            "group2": [
                {}
            ]
        }
    ],
    "Key1": "Value1",
    "Key2": "Value2"
}

我能做的最好的事情就是解析 JSON，并删除该元素(如果存在)。但是，这没有考虑数组或嵌套 JSON。以下代码仅删除“userid”:“John991”。

 var b1 = JSON.parse(JSON);

 if (b1.hasOwnProperty("userid")){
    delete b1["userid"];
 }

Answer 1

您可以创建一个迭代键并以递归方式删除键的函数。像这样的事情

const input = {
  "userId": "John991",
  "group1": {
      "color": "red",
      "height": "100",
      "userid": "John992"
  },
  "data": [
      {
          "userid": "John993",
          "Key3": "Value3"
      },
      {
          "group2": [{
              "userid": "John994"
          }]
      }
  ],
  "Key1": "Value1",
  "Key2": "Value2"
};


function deleteKey(obj, keyToDelete) {
  Object.keys(obj).forEach(key => {
    if (key.toLowerCase() === keyToDelete) {
      delete obj[key];
    }
    value = obj[key];
    if (value instanceof Object) {
      deleteKey(value, keyToDelete);
    }
  });
}
deleteKey(input, "userid");

console.log(JSON.stringify(input, null, 2));