javascript - 分割空格并搜索用户输入

Question

我有一个输入字段，用户可以在其中搜索数据库中的某个名称。该数据库包含诸如“Doe, John”之类的名称。

如果用户搜索“john”，我认为这很容易实现。但是，如果他或她搜索“john Doe”，我想实现对 john 或搜索 doe 的逻辑搜索。

对于正则表达式，我完全迷失了。这样的事情有可能吗？然而，有了 JS，我至少可以考虑这个算法:

• 将输入拆分为空格并创建数组
• 删除特殊字符
• 过滤从数据库检索的 JSON 对象
• 检查 item 是否包含清理后的字符串数组

至于 JS 函数，我尝试了一些东西(徒劳):

        let search = 'John Doe' //user input
        let data = ['Doe, John', 'Bean, Mister'] //data from database
        let split = search.split(" ") //split the whitespace into two arrays
        split = split.map(item => { return item.replace(/[^\w\s]+/gi, '')}) //remove dots, commas etc.
        let result = data.filter(item => { //filter each item from the data... 
            split.forEach(element => {
            let found = item.match(new RegExp(element, "i")) // so here I get matches, but how can I move them up the let the filter method return true?
            return found.length
            }).length>0


        })
        console.log(result)

感谢Taplars的评论，我使用了map方法而不是forEach:

let data = ['Doe, John', 'Bean, Mister']
    let split = search.split(" ")
    split = split.map(item => { return item.replace(/[^\w\s]+/gi, '')})
    let result = data.filter(item => {
      let filtered =   split.map(element => { 
            let ret = item.match(new RegExp(element, "i"))
            return ret
        })
      console.log(item,filtered) //now I have two arrays, one with something meaningful and one with [null,null]. How can I remove empty arrays?
      return filtered.length>0 
    })
    console.log(result)

Answer 1

尝试以下操作:

• 获取搜索表达式并将其转换为一系列正则表达式
• 迭代数据并检查部分或所有表达式是否匹配

const data = ['Doe, John', 'Doe, Jane', 'Smith, John', 'Bean, Mister'] // data from database

function searchEvery(input) {
  const wordExpressions = input.split(/[^\w]+/g)
    .filter(word => word) // remove empty entries
    .map(word => new RegExp(word, 'i')); // convert to regular expression
  return data.filter(item => wordExpressions.every(exp => exp.test(item)));
}

function searchSome(input) {
  const wordExpressions = input.split(/[^\w]+/g)
    .filter(word => word) // remove empty entries
    .map(word => new RegExp(word, 'i')); // convert to regular expression
  return data.filter(item => wordExpressions.some(exp => exp.test(item)));
}

console.log(searchEvery('John Doe'))
console.log(searchEvery('John'))
console.log(searchEvery('Doe'))

console.log(searchSome('John Doe'))