python - 如何使用字典关联多个事物？

Question

我有很多东西想要相互关联。

例如，A、B 和 C

我希望“A”给“B”，“B”给“C”。目前，我只能想到创建两个单独的词典。以下文本表输出显示了我在字典中的内容。

字典“d”:

+--------------------------------------+--------------------------------------+
|                 Key                  |                Value                 |
+======================================+======================================+
| 3223612326                           | ['192.168.249.132:47671>192.168.249. |
|                                      | 133:80', '192.168.249.132:9065>192.1 |
|                                      | 68.249.133:80', '192.168.249.132:626 |
|                                      | 6>192.168.249.133:80']               |
+--------------------------------------+--------------------------------------+
| 3118051391                           | ['192.168.249.132:10867>192.168.249. |
|                                      | 133:80', '192.168.249.132:20275>192. |
|                                      | 168.249.133:80', '192.168.249.132:37 |
|                                      | 189>192.168.249.133:80']             |
+--------------------------------------+--------------------------------------+

字典“e”:

+------------------------------------------+-------+
|                   Key                    | Value |
+==========================================+=======+
| 192.168.249.132:20275>192.168.249.133:80 | ll    |
+------------------------------------------+-------+
| 192.168.249.132:9065>192.168.249.133:80  | ll    |
+------------------------------------------+-------+
| 192.168.249.132:47671>192.168.249.133:80 | He    |
+------------------------------------------+-------+
| 192.168.249.132:37189>192.168.249.133:80 | o     |
+------------------------------------------+-------+
| 192.168.249.132:10867>192.168.249.133:80 | He    |
+------------------------------------------+-------+
| 192.168.249.132:6266>192.168.249.133:80  | o     |
+------------------------------------------+-------+

如您所见，字典“e”使用字典“d”中的每个值作为其键。这给我带来了很多问题，因为我必须链接两个不同词典之间的所有内容。有没有更好的方法在 python 中实现这一点？使用字典或其他容器。

更新

用于向字典 'd' 添加内容的代码类似于:

def dictionaryd(sip, sport, dip, dport, key):

 d = dict()

 value =  str(sip) + ":" + str(sport) +  ">" + str(dip)+  ":" + str(dport)

 if key in d:
  if value not in d[key]: 
      d[key].append(value)
 else:
  d[key] = [value]

Answer 1

根据您提供的元素，e 字典的值对于每个 key，意味着您可以在一个元组中使用它:

{ 3223612326 : [('192.168.249.132:20275>192.168.249.133:80', 'll'),
                ('192.168.249.132:9065>192.168.249.133:80', 'll'),
                ('192.168.249.132:6266>192.168.249.133:80', 'He')],
  3118051391 : [('192.168.249.132:10867>192.168.249.133:80', 'o'),
                ('192.168.249.132:20275>192.168.249.133:80', 'He'),
                ('192.168.249.132:37189>192.168.249.133:80', 'o')]
}

如果你想要更方便的东西，你可以使用 NamedTuple:

from collections import namedtuple

RouteEntry = namedtuple('RouteEntry', ['route', 'comment'])

{ 3223612326 : [RouteEntry(route='192.168.249.132:20275>192.168.249.133:80', comment='ll'),
                RouteEntry(route='192.168.249.132:9065>192.168.249.133:80',  comment='ll'),
                RouteEntry(route='192.168.249.132:6266>192.168.249.133:80',  comment='He')],
  3118051391 : [RouteEntry(route='192.168.249.132:10867>192.168.249.133:80', comment='o'),
                RouteEntry(route='192.168.249.132:20275>192.168.249.133:80', comment='He'),
                RouteEntry(route='192.168.249.132:37189>192.168.249.133:80', comment='o')]
}

---

这是我对你的问题的看法，我当然做了假设，比如 e 表键是函数执行时的时间戳。这就是为什么对于测试用例，我使用 time.sleep(1) 在 route_table 中有两个箭头。

我也试着解释你的数据，它看起来像一个路由表，总是避免在程序中使用e，d这样的名字，并且总是尝试使用相关名称，以便您的读者了解您在做什么。

import time
from collections import namedtuple

SourceAddress = namedtuple('SourceAddress', ['ip', 'port'])
DestinationAddress = namedtuple('DestinationAddress', ['ip', 'port'])
RouteEntry = namedtuple('RouteEntry', ['source', 'destination', 'comment'])

def save_routes(table, sip, sport, dip, dport, key):
    src = SourceAddress(sip, sport)
    dst = DestinationAddress(dip, dport)
    entry = RouteEntry(src, dst, key)

    table.setdefault(int(time.time()), []).append(entry)

route_table = {}

save_routes(route_table, '192.168.249.132', '20275', '192.168.249.133', '80', 'll')
save_routes(route_table, '192.168.249.132', '9065', '192.168.249.133', '80', 'll')
save_routes(route_table, '192.168.249.132', '6266', '192.168.249.133', '80', 'He')
time.sleep(1)
save_routes(route_table, '192.168.249.132', '10867', '192.168.249.133', '80', 'o')
save_routes(route_table, '192.168.249.132', '20275', '192.168.249.133', '80', 'He')
save_routes(route_table, '192.168.249.132', '37189', '192.168.249.133', '80', 'o')

---

My question is more on the general level of how do we link 3 things using maybe 1 dictionary

这类问题的答案通常是使用元组 或使用类实例。最终真正的问题是您将如何使用您的数据，以及如何根据您的数据集优化数据的构建和读取。

总而言之，您的问题并不是真正的 python 问题，而是一般问题。

HTH