php - 如何在 JavaScript 代码中包含 php 文件(top.php)？

Question

如果满足条件，我想将一个名为 top.php 的 php 文件包含到我的 javascript 代码中。这是用于检查浏览器版本的代码。我需要的是检查浏览器名称，如果是 chrome，则只需要显示 top.php 文件。但在每个浏览器中的这段代码中，它都包含该页面。

<script type="text/javascript">
    var nVer = navigator.appVersion;
    var nAgt = navigator.userAgent;
    var browserName  = navigator.appName;
    var fullVersion  = ''+parseFloat(navigator.appVersion); 
    var majorVersion = parseInt(navigator.appVersion,10);
    var nameOffset,verOffset,ix;

    // In Opera, the true version is after "Opera" or after "Version"
    if ((verOffset=nAgt.indexOf("Opera"))!=-1) {
     browserName = "Opera";
     fullVersion = nAgt.substring(verOffset+6);
     if ((verOffset=nAgt.indexOf("Version"))!=-1) 
       fullVersion = nAgt.substring(verOffset+8);
    }
    // In MSIE, the true version is after "MSIE" in userAgent
    else if ((verOffset=nAgt.indexOf("MSIE"))!=-1) {
     browserName = "Microsoft Internet Explorer";
     fullVersion = nAgt.substring(verOffset+5);
    }
    // In Chrome, the true version is after "Chrome" 
    else if ((verOffset=nAgt.indexOf("Chrome"))!=-1) {
     browserName = "Chrome";
     fullVersion = nAgt.substring(verOffset+7);
    }
    // In Safari, the true version is after "Safari" or after "Version" 
    else if ((verOffset=nAgt.indexOf("Safari"))!=-1) {
     browserName = "Safari";
     fullVersion = nAgt.substring(verOffset+7);
     if ((verOffset=nAgt.indexOf("Version"))!=-1) 
       fullVersion = nAgt.substring(verOffset+8);
    }
    // In Firefox, the true version is after "Firefox" 
    else if ((verOffset=nAgt.indexOf("Firefox"))!=-1) {
     browserName = "Firefox";
     fullVersion = nAgt.substring(verOffset+8);
    }
    // In most other browsers, "name/version" is at the end of userAgent 
    else if ( (nameOffset=nAgt.lastIndexOf(' ')+1) < 
              (verOffset=nAgt.lastIndexOf('/')) ) 
    {
     browserName = nAgt.substring(nameOffset,verOffset);
     fullVersion = nAgt.substring(verOffset+1);
     if (browserName.toLowerCase()==browserName.toUpperCase()) {
      browserName = navigator.appName;
     }
    }
    // trim the fullVersion string at semicolon/space if present
    if ((ix=fullVersion.indexOf(";"))!=-1)
       fullVersion=fullVersion.substring(0,ix);
    if ((ix=fullVersion.indexOf(" "))!=-1)
       fullVersion=fullVersion.substring(0,ix);

    majorVersion = parseInt(''+fullVersion,10);
    if (isNaN(majorVersion)) {
     fullVersion  = ''+parseFloat(navigator.appVersion); 
     majorVersion = parseInt(navigator.appVersion,10);
    }

    document.write(''
     +'Browser name  = '+browserName+'<br>'
     +'Full version  = '+fullVersion+'<br>'
     +'Major version = '+majorVersion+'<br>'
     +'navigator.appName = '+navigator.appName+'<br>'
     +'navigator.userAgent = '+navigator.userAgent+'<br>'
    )
    var OSName="Unknown OS";
    if (navigator.appVersion.indexOf("Win")!=-1) OSName="Windows";
    if (navigator.appVersion.indexOf("Mac")!=-1) OSName="MacOS";
    if (navigator.appVersion.indexOf("X11")!=-1) OSName="UNIX";
    if (navigator.appVersion.indexOf("Linux")!=-1) OSName="Linux";
    document.write('Your OS: '+OSName+'<br>');
    if(browserName ==  'Chrome')
    {
    document.write("u r using chrome "+fullVersion);
    <?php include("top.php") ?> ;

    }
    else {
    alert("Not chrome");
    }
    </script>

Answer 1

你不能也不应该。浏览器不执行任何 PHP 代码。

what i need is to check the browser name and if its chrome then only need to display the top.php file. But in this code in every browser it include that page.

我反对在服务器端做这样的事情，但如果你必须这样做，你可以尝试通过检查请求 header 来通过 PHP 来检查浏览器。

尝试检查$_SERVER['HTTP_USER_AGENT']。

另请参阅:http://php.net/manual/en/function.get-browser.php