php - 想要停止倒计时并随着时间的推移给出输出

Question

你好，我想当我的倒计时结束时，它应该显示为:

document.getElementById("remain").innerHTML = "Time up";

此处实时倒计时:http://ffsng.deewayz.in/counter/

由于它即将结束，我想发出“时间到了”

我尝试了一些方法，但没有成功。

function setCountDown() {
    seconds--;
    if (seconds < 0) {
        minutes--;
        seconds = 59;
    }
    if (minutes < 0) {
        hours--;
        minutes = 59;
    }
    if (hours < 0) {
        days--;
        hours = 23;
    }
    document.getElementById("remain").innerHTML = days + " days, " + hours + " hours, " + minutes + " minutes, " + seconds + " seconds";
    if ((seconds = 0) && (minutes = 0) && (hours = 0) && (days = 0))(
        document.getElementById("remain").innerHTML = "time up";
    ) else ( 
        setTimeout("setCountDown()", 1000);
    );  
}

我的完整代码在这里:Countdown timer not working with gmt time

Answer 1

不太好，但可以满足您的需求!

HTML

<div id="countdown">
    <span id="row1"></span><br />
    <span id="row2"></span>
</div>

JS

var end = new Date('October 08, 2012 00:55:00');

function toSt1(n) {
    var s = '';
    if (n < 10) s += '0';
    return (s + n).toString();
}

function toSt2(n) {
    var s = '';
    if (n < 10) s += '00';
    else if (n < 100) s += '0';
    return (s + n).toString();
}

var countdown = function() {
    var d = new Date();
    var count = Math.floor(end.getTime() - d.getTime());
    if (count > 0) {
        var miliseconds = toSt2(count % 1000);
        count = Math.floor(count / 1000);
        var seconds = toSt1(count % 60);
        count = Math.floor(count / 60);
        var minutes = toSt1(count % 60);
        count = Math.floor(count / 60);
        var hours = toSt1(count % 24);
        count = Math.floor(count / 24);
        var days = count;
        document.getElementById('row1').innerHTML = days + ' Days';
        document.getElementById('row2').innerHTML = hours + ' Hours ' + minutes + ' Minutes ' + seconds + ' Seconds ';
        setTimeout('countdown()', 100);
    } else {
        document.getElementById("countdown").innerHTML = "Time up";
    }
}
countdown();

<强> DEMO