html - 如何在 css 中重新设置 radio 类型的输入样式？

Question

我想创建自己的单选按钮，但似乎无法重新设计它们的样式。

我得到了以下 html:

.segment {
  all: unset;
  position: relative;
  border: solid 1px blue;
  height: 2rem;
  width: 3rem;
  -webkit-tap-highlight-color: transparent;
}

<div>
  <input id="segemnt0" class="segment" type="radio" name="segment">
  <input id="segemnt1" class="segment" type="radio" name="segment">
  <input id="segemnt2" class="segment" type="radio" name="segment">
</div>

这是行不通的。什么都不显示。如果我删除“all: unset;”它只显示没有边框等的普通样式的复选框...

Answer 1

您可以自定义单选按钮添加 <label>标记和 CSS

这是可能对您有帮助的 fiddle :

[type="radio"]:checked,
[type="radio"]:not(:checked) {
  position: absolute;
  left: -9999px;
}

[type="radio"]:checked+label,
[type="radio"]:not(:checked)+label {
  position: relative;
  padding-left: 28px;
  cursor: pointer;
  line-height: 20px;
  display: inline-block;
  color: #666;
}

[type="radio"]:checked+label:before,
[type="radio"]:not(:checked)+label:before {
  content: '';
  position: absolute;
  left: 0;
  top: 0;
  width: 18px;
  height: 18px;
  border: 1px solid #ddd;
  border-radius: 100%;
  background: #fff;
}

[type="radio"]:checked+label:after,
[type="radio"]:not(:checked)+label:after {
  content: '';
  width: 12px;
  height: 12px;
  background: #F87DA9;
  position: absolute;
  top: 4px;
  left: 4px;
  border-radius: 100%;
  -webkit-transition: all 0.2s ease;
  transition: all 0.2s ease;
}

[type="radio"]:not(:checked)+label:after {
  opacity: 0;
  -webkit-transform: scale(0);
  transform: scale(0);
}

[type="radio"]:checked+label:after {
  opacity: 1;
  -webkit-transform: scale(1);
  transform: scale(1);
}

<input id="segemnt0" class="segment" type="radio" name="segment">
<label for="segemnt0">one</label>
<input id="segemnt1" class="segment" type="radio" name="segment">
<label for="segemnt1">two</label>
<input id="segemnt2" class="segment" type="radio" name="segment">
<label for="segemnt2">three</label>