swift - 如何将带有“字符的字符串转换为URL

Question

如何把"fff\"fff"这样的String转成URL？URL 必须包含 "字符并且类似于 "ff"ff"

Answer 1

您将 " 字符转义为 %22。最简单的方法是通过 URLComponents:

var components = URLComponents(string: "https://somewhere.com")!
components.query = "ff\"ff"

let url = components.url! // https://somewhere.com?ff%22ff