php - 如何使用 PHP 抓取此内容并仅获取纬度/经度

Question

比如说，我有这个代码:

var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(33.013489, -117.140167);

map.setCenter(latlng, 9);
map.panTo(latlng);

var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(32.979286, -117.02623);

map.setCenter(latlng, 9);
map.panTo(latlng);

var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(32.746319, -117.141449);

map.setCenter(latlng, 9);
map.panTo(latlng);

var i = new GIcon(G_DEFAULT_ICON);
var latlng = new GLatLng(32.758286, -117.125053);

map.setCenter(latlng, 9);
map.panTo(latlng);

如何使用 PHP 返回列表或仅返回纬度和经度。所以 GLatLng()

之间的任何内容

所以我最终会得到一个看起来像这样的数组:

32.758286, -117.125053
32.979286, -117.02623
32.746319, -117.141449
32.758286, -117.125053

Answer 1

preg_match_all('~
    (?<=\()            (?# starts with opening parentheses )
    (?P<lat>[\d.-]+)   (?# then a digit, dot or dash more than one time )
    \s*,\s*            (?# followed by a comma with any number of spaces around )
    (?P<lng>[\d.-]+)   (?# then another digit, dot or dash more than one time )
    (?=\))             (?# ends with closing parentheses )
~x', $str, $matches);
var_dump($matches);