gpt4 book ai didi

php - 没有收到来自 php 的电子邮件

转载 作者:行者123 更新时间:2023-11-28 15:56:26 24 4
gpt4 key购买 nike

我知道当我的 JavaScript 结果正在运行时,我从此流程文件中收到状态“1”。问题是我没有收到电子邮件。

<?php
//Retrieve form data.
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment'];
//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;
//Simple server side validation for POST data, of course,
//you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.';
if (!$comment) $errors[count($errors)] = 'Please enter your comment.';
//if the errors array is empty, send the mail
if (!$errors) {
//recipient - change this to your name and email
$to = 'myemail@gmail.com';
//sender
$from = $name . ' <' . $email . '>';

//subject and the html message
$subject = 'Comment from ' . $name;
$message = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head></head>
<body>
<table>
<tr><td>Name</td><td>' . $name . '</td></tr>
<tr><td>Email</td><td>' . $email . '</td></tr>
<tr><td>Comment</td><td>' . nl2br($comment) . '</td></tr>
</table>
</body>
</html>';
//send the mail
$result = sendmail($to, $subject, $message, $from);

//if POST was used, display the message straight away
if ($_POST) {
if ($result) echo 'Thank you! We have received your message.';
else echo 'Sorry, unexpected error. Please try again later';

//else if GET was used, return the boolean value so that
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
echo $result;
}
//if the errors array has values
} else {
//display the errors message
for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
echo '<a href="form.php">Back</a>';
exit;
}
//Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= 'From: ' . $from . "\r\n";

$result = mail($to,$subject,$message,$headers);

if ($result) return 1;
else return 0;
}
?>

最佳答案

您提到您正在使用 GoDaddy。 GoDaddy 要求您合法设置发件人地址,以匹配其发送源的网站域,或使用 SMTP 进行身份验证。

这种发送电子邮件的方法存在巨大的漏洞。垃圾邮件发送者可以通过插入其他收件人轻松覆盖发件人: header 。

我不确定您的应用程序计划如何以邮件为中心,但我建议使用像 PHPMailerPEAR::Mail 这样的包,因为它会处理为您提供更高水平的电子邮件处理。这可以让您专注于应用程序中更重要的部分。内置的 PHP mail() 功能的功能非常有限,当您尝试扩展邮件功能时,您将遇到许多基础 mail() 所遇到的障碍。如果没有大量额外的逻辑(例如附件、MIME 类型等),code> 函数就无法处理。

关于php - 没有收到来自 php 的电子邮件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18626792/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com