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按日期快速排序核心数据(不仅仅是时间)

转载 作者:行者123 更新时间:2023-11-28 15:53:32 24 4
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我正在使用核心数据在 Swift 中构建一个应用程序。我正在使用具有日期属性的任务实体。我需要根据这个截止日期对任务进行排序。

我尝试使用带有到期键的 NSSortDescriptor

NSSortDescriptor.init(key: "due", ascending: false)

问题:

它仅按时间对我的数据进行排序 - 不考虑日/月/年

这是我从获取请求中获得的数据:

Optional(2017-02-06 03:29:18 +0000)
Optional(2017-02-08 03:29:27 +0000)
Optional(2017-02-07 03:29:38 +0000)
Optional(2017-02-08 03:30:29 +0000)

我怎样才能按先到先得的排序? (考虑整个 NSDate 而不仅仅是时间部分)

我希望它是:

Optional(2017-02-06 03:29:18 +0000)
Optional(2017-02-07 03:29:38 +0000)
Optional(2017-02-08 03:29:27 +0000)
Optional(2017-02-08 03:30:29 +0000)

完整代码 所有完成的任务在列表中都是 0,我正在调用:

helper(showComp: true, sortBy: NSSortDescriptor.init(key: "due", ascending: false))

辅助函数:

func helper(showComp: Bool, sortBy: NSSortDescriptor?){
let g = cur as! Group
guard let appDelegate = UIApplication.shared.delegate as? AppDelegate else {
return
}

let managedContext = appDelegate.persistentContainer.viewContext

let fetchRequest = NSFetchRequest<NSManagedObject>(entityName: "Task")
let sortDescriptor0 = NSSortDescriptor.init(key: "completed", ascending: true)
let sortDescriptor = NSSortDescriptor.init(key: "index", ascending: true)
if sortBy == nil {
fetchRequest.sortDescriptors = [sortDescriptor0, sortDescriptor]
}else{
fetchRequest.sortDescriptors = [sortDescriptor0, sortBy!]
}
if (cur as! Group).name != "All"{
var predicate = NSPredicate(format: "group = %@", argumentArray: [g])
if !showComp {
predicate = NSPredicate(format: "group = %@ && completed = %@", argumentArray: [g, 0])
}
fetchRequest.predicate = predicate
}
do {
groups = try managedContext.fetch(fetchRequest)
} catch let error as NSError {
print("Could not fetch. \(error), \(error.userInfo)")
}

核心数据属性照片 enter image description here

最佳答案

swift 3

var sdSortDate = NSSortDescriptor.init(key: "date", ascending: false)
fr.sortDescriptors = [sdSortDate]
let result4 = try! context.fetch(fr)

我在 Swift 3 中测试过它,效果很好

[<NSManagedObject: 0x618000089060> (entity: CoreDate; id: 0x61800002c460 <x-coredata://E7D9FD6F-5DCF-464B-93BF-D1609BF35695/CoreDate/p3> ; data: {
date = "2017-02-09 21:35:19 +0000";
}), <NSManagedObject: 0x61800008b680> (entity: CoreDate; id: 0x60000002c140 <x-coredata://E7D9FD6F-5DCF-464B-93BF-D1609BF35695/CoreDate/p1> ; data: {
date = "2017-02-06 04:41:59 +0000";
}), <NSManagedObject: 0x60800008c080> (entity: CoreDate; id: 0x60800002d460 <x-coredata://E7D9FD6F-5DCF-464B-93BF-D1609BF35695/CoreDate/p2> ; data: {
date = "2017-02-17 18:28:39 +0000";
})]

After sort

[<NSManagedObject: 0x61800008b680> (entity: CoreDate; id: 0x60000002c140 <x-coredata://E7D9FD6F-5DCF-464B-93BF-D1609BF35695/CoreDate/p1> ; data: {
date = "2017-02-06 04:41:59 +0000";
}), <NSManagedObject: 0x618000089060> (entity: CoreDate; id: 0x61800002c460 <x-coredata://E7D9FD6F-5DCF-464B-93BF-D1609BF35695/CoreDate/p3> ; data: {
date = "2017-02-09 21:35:19 +0000";
}), <NSManagedObject: 0x60800008c080> (entity: CoreDate; id: 0x60800002d460 <x-coredata://E7D9FD6F-5DCF-464B-93BF-D1609BF35695/CoreDate/p2> ; data: {
date = "2017-02-17 18:28:39 +0000";
})]

关于按日期快速排序核心数据(不仅仅是时间),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42060112/

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