javascript - 为什么我无法在JQuery中获取变量值

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已关闭 9 年前。

我开发了使用 JQuery 获取 JSON 数据的工具，但问题是有些变量没有放置它们的值，并且我只得到了像文本一样的变量名称。这是代码

$(document).ready(function(){
$('.HTML').each(function(){
var call = $.getJSON('http://test-khamsat-support-gig.blogspot.com/feeds/posts/default/-/Break?max-results=10&orderby=published&alt=json-in-script&callback=?',function(data){
var cont = data.version;
    });

    var th = $(this);
     var b = th.html(),
            a = b.match(/[^[\]]+(?=])/g);
          if(a){
            if(a[2] == 'one'){
                th.append("<h1>'+cont+'</h1>")
            }
          }
    }); 
  });

该代码将仅在我的博客中运行，因为它内容是我的 blog饲料

Answer 1

尝试

$(document).ready(function () {
    $('.HTML').each(function () {
        //store the reference to the element to use inside the callback
        var th = $(this);
        $.getJSON('http://test-khamsat-support-gig.blogspot.com/feeds/posts/default/-/Break?max-results=10&orderby=published&alt=json-in-script&callback=?', function (data) {
            var cont = data.version;

            //move this inside the ajax callback to support async nature
            var b = th.html(),
                a = b.match(/[^[\]]+(?=])/g);
            if (a) {
                if (a[2] == 'one') {
                    //use proper string concatenation here
                    th.append('<h1>' + cont + '</h1>')
                }
            }
        });
    });
});

• How to return the response from an AJAX call?