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swift - 用一个函数返回几个结果

转载 作者:行者123 更新时间:2023-11-28 15:36:05 24 4
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我想使用多个函数(如最小值、最大值...)并使用函数 determineStatistics 返回所有结果,以将考试 block 变为真。

我尝试添加一个初始化并返回统计类。但我认为这不是解决问题的正确方法?

class statistic{
var Minimum:Int?;
var Maximum:Int?;
var Average:Double?;
var Median:Double?;

init (Minimum:Int?, Maximum:Int?, Average:Double?, Median:Double?){
self.Minimum=Minimum;
self.Maximum=Maximum;
self.Average=Average;
self.Median=Median;
}

}



func Summ(input input:[Double]) -> Double? {
var memory:Double=0;

if input.count == 0{
return nil
}

for number in input{
memory=memory+number
}
return memory;
}

func Average(input input:[Double]) -> Double? {
var sum=Summ(input: input)
var countedInput:Double = Double(input.count)

if countedInput == 0.0{
return nil
}

return sum!/countedInput;
}

func Minimum(input input:[Int]) -> Int? {
var memory:Int?=0;

if input.count == 0{
return nil
}

for i in input{
for j in input{
if i<j{
memory=i;
}
}
}
return memory;
}

func Maximum(input input:[Int]) -> Int? {
var memory:Int=0;

if input.count == 0{
return nil
}

for i in input{
for j in input{
if i>j{
memory=i;
}
}
}
return memory;
}

func sort(input input:[Int]) -> [Int] {
var data = input

for i in 0..<data.count-1{
for j in 0..<data.count-1{
if (data[j] > data[j+1]){
var temp = data[j+1]
data[j+1] = data[j]
data[j+1] = temp
}
}
}
return data;
}


func Median(input input:[Int]) -> Int? {

if input.count == 0{
return nil
}

var median = sort(input: input)
var medi = input.count
var me = medi/2

return median[me]
}


//The function determineStatistics() should output a statistic-object with all calculable datas

func determineStatistics(_ input:[Int]) -> statistic {
var result = statistic(Minimum: Minimum(input: input),Maximum: Maximum(input: input),Average: Average(input: input),Median: Median(input: input));
return result;
}
//here I get the error: Cannot convert value of type [Int] to expected argument type [Double]

//exam block - sould turn true
let a4adata = determineStatistics([1,2,3,4,5,6,7,8,9,10]);
let a4a = a4adata.Minimum == 1 && a4adata.Maximum == 10 && a4adata.Average == 5.5 && a4adata.Median == 6;
let a4bdata = determineStatistics([]);
let a4b = a4bdata.Minimum == nil && a4bdata.Maximum == nil && a4bdata.Average == nil && a4bdata.Median == nil;
let a4 = a4a && a4b;

我不知道从哪里开始解决问题并将 exam-block 变为 true。

最佳答案

伙计,如果你必须在 Swift 中这样做,请用大写字母声明类,用小写字母声明变量,函数以小写字母开头。

class Statistic {

var minimum: Int?
var maximum: Int?
var average: Double?
var median: Double?
}

停止检查数组数量

if input.count == 0 {
return nil
}

并使用优化

if input.isEmpty {
return nil
}

甚至更快

guard !input.isEmpty else { return nil }

您可能将 Statistic 类中声明为 Double 的中值与声明为 Int 的中值函数的输出混合在一起?

试试这个。在这里和那里做了一些事情,它可以做得更好,所以试着多清理一下。有改进的余地。

    struct Statistic {

var minimum: Int?
var maximum: Int?
var average: Double?
var median: Int?
}

func summFunc(input input: [Double]) -> Double? {

guard !input.isEmpty else { return nil }

return input.reduce(0, +)
}

func averageFunc(input input: [Double]) -> Double? {

guard !input.isEmpty else { return nil }

var sum = summFunc(input: input)

return sum! / Double(input.count)
}

func minimumFunc(input input: [Int]) -> Int? {

guard !input.isEmpty else { return nil }

return input.minElement()
}

func maximumFunc(input input: [Int]) -> Int? {

guard !input.isEmpty else { return nil }

return input.maxElement()
}

func sortFunc(input input: [Int]) -> [Int] {
return input.sorted { $0 < $1 }
}

func medianFunc(input input: [Int]) -> Int? {

guard !input.isEmpty else { return nil }

var median = sortFunc(input: input)
let medi = input.count
let me = medi/2

return median[me]
}

func determineStatistics(_ input:[Int]) -> Statistic {

return Statistic(minimum: minimumFunc(input: input),
maximum: maximumFunc(input: input),
average: averageFunc(input: input.map { Double($0) } ),
median: medianFunc(input: input))
}

let a4adata = determineStatistics([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])
let a4a = a4adata.minimum == 1 && a4adata.maximum == 10 && a4adata.average == 5.5 && a4adata.median == 6

let a4bdata = determineStatistics([])
let a4b = a4bdata.minimum == nil && a4bdata.maximum == nil && a4bdata.average == nil && a4bdata.median == nil
let a4 = a4a && a4b

而且我使用了 struct 而不是 class,所以我不必编写初始化程序。可能有更多的 var 可以更改为 let。

关于swift - 用一个函数返回几个结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44249294/

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