ios - Alamofire 4.4.0 : Extra Argument 'Method' in Call: Do not know What is Throwing Error

Question

我在 swift 中有一个 alamofire 请求，我不确定为什么它会抛出 Extra Argument 'Method' in Call:

Alamofire.request(
                URL(string: "https://api.io"),
                method: .post,
                parameters: [
                    "grant_type": "client_credentials",
                    "client_id": "user00941",
                    "client_secret": "ILGddu8y8g7qW"
                ],
                encoding: .urlEncodedInURL
                ).response {

                    request, response, data, error in

                    let json = JSON(data: data!)

                    print("OAuth 2 token obtained from API: \(json["access_token"])")

                    let token = "Bearer \(json["access_token"].stringValue)"

            }

我一直在查看其他各种帖子，但似乎找不到适合我的代码的解决方案。

Answer 1

your original code 的问题是你在使用 argument label url 即使 Alamofire.request function signature省略了它:

public func request(
    _ url: URLConvertible,
    method: HTTPMethod = .get,
    parameters: Parameters? = nil,
    encoding: ParameterEncoding = URLEncoding.default,
    headers: HTTPHeaders? = nil)
    -> DataRequest

从您的函数调用中删除 url: 将解决那个错误，但是 Swift 应该会提醒您“可选类型 'URL 的值？'” [是] 没有展开。”尽管您可以使用forced unwrapping要提取 URL 的值，我建议使用 optional binding相反:

if let url = URL(string: "https://api.io") {
    Alamofire.request(
                    URL(string: "https://api.io"),
                    method: .post,
                    parameters: [
                        "grant_type": "client_credentials",
                        "client_id": "user00941",
                        "client_secret": "ILGddu8y8g7qW"
                    ],
                    encoding: .urlEncodedInURL
                    ).response {
                        request, response, data, error in

                        let json = JSON(data: data!)

                        print("OAuth 2 token obtained from API: \(json["access_token"])")

                        let token = "Bearer \(json["access_token"].stringValue)"
                   }
}

或者，您可以使用 guard 语句来保留 Golden Path通过您的代码:

guard let url = URL(string: "https://api.io") else {
    return
}