ios - Swift:重用代码将类传递给参数

Question

我想重用代码，所以我创建了 redirectToTabBarControllerChild

func redirectToTabBarControllerChild(storyboardName: String, tabBarIndex: Int, segueID: String, viewController: UITableViewController) {
    let storyboardMain = UIStoryboard(name: storyboardName, bundle: nil)
    let tabBarController = storyboardMain.instantiateViewController(withIdentifier: "TabBarController") as! UITabBarController
    window?.rootViewController = tabBarController
    tabBarController.selectedIndex = tabBarIndex
    let navigationViewContrller = tabBarController.childViewControllers[tabBarIndex] as! UINavigationController
    let currentViewContrller = navigationViewContrller.childViewControllers.first as! viewController
    currentViewContrller.performSegue(withIdentifier: segueID, sender: nil)
    window?.makeKeyAndVisible()
}

例如，我想传递给 ProfileViewController 的最后一个参数。但是我在这一行中有一个错误: let currentViewContrller = navigationViewContrller.childViewControllers.first as! View Controller

使用未声明类型的viewController

有人知道我该怎么做吗？

Answer 1

navigationController?.childViewControllers 是 UIViewControllers 的数组。您将获得 first 属性，这意味着您需要将其转换为 as! UIViewController 这将强制转换它并且它不再是可选的。

你想要做的是将它转换为 UITableViewController，所以这样做:

if let vc = navigationViewContrller.childViewControllers.first as? UITableViewController {
    // Will succeed if the first is of type UITableViewController
    // Use vc in here
}