javascript - 从函数返回多个值

Question

我有一个 js 文件(如下)，其中每个函数返回 2 个结果(Step1 和 Step2)。我需要将这些结果转换成...

“将”+(第 1 步产品类型)+“与“+(第 1 步过氧化物)+“混合。”+(第 1 步计时)

使用“+(Step2产品类型)+”，将“+(Step2toneCalc)+”与“+(Step2过氧化物)+”混合。 "+ (Step2 计时)

将这些结果转换为上述格式的最佳方法是什么？
我知道如何处理单个值，但不太确定如何处理包含在一个函数中的多个函数。

谢谢

function doubleprocess(type) {

   function productType() {
    var step1;
    var step2;
    if (type == "light") {
        step1 = "lightner";
        step2 = "demi-color";
    } else {
        step1 = "demi-color";
        step2 = "demi-color";
    }
    return step1, step2;
   }


   function toneCalc() {
    var step1;
    var step2;

    if (type == "light") {
        step1 = "light gold";
    } else if (type == "dark") {
        step1 = "80% gold with 20% red"
    } else {
        step1 = "another tone";
    }

    step2 = "neutral";

    return step1, step2;
   }

   function peroxide() {
    var step1;
    var step2;

    if (type == "light") {
        step1 == "20V/6% peroxide";
    } else if (type == "dark") {
        step1 = "something else";
    } else {
        step1 = "Do something.";
    }
    step2 = "Do something else.";
    return step1, step2;
   }

   function level() {
    var step1 = "";
    var step2;

    if (type == "dark") {
        step1 = "Do something.";
    } else {
        step1 = "Do Nothing.";
    };

    step2 = "Do something.";

    return step1, step2;
   }

   function timing() {
    var step1;
    var step2;
    if (type == "light") {
        step1 == "Do something.";
        step2 = "Do something.";
    } else if (type == "dark") {
        step1 = "Do something.";
        step2 = "Do something.";
    } else {
        step1 = "Do something.";
        step2 = "Do something.";
    }
     return step1, step2;
   }
 }

Answer 1

不能从一个函数返回多个变量。但是您可以返回一个对象。

function peroxide() {
    var step1;
    var step2;

    if (type == "light") {
        step1 == "20V/6% peroxide";
    } else if (type == "dark") {
        step1 = "something else";
    } else {
        step1 = "Do something.";
    }
    step2 = "Do something else.";
    var rtn = new Object();
    rtn.step1 = step1;
    rtn.step2 = step2;
    return rtn;
   }