javascript - 正则表达式查找字符串末尾的单词

Question

我有字符串，根据该字符串的结束字符，我需要检查条件。我已经设法编写了以下脚本，但它没有按照我的预期进行。

//var receivers_type = "d2845a48f91b29f9d0a6e96858f05d85xing";
var receivers_type = "d21fca8635940e97d0f8e132d806cedaxingpage";
if (/.*xing/.test(receivers_type)) {
    console.log('xing profile');
    flag = 1;
}
if (/.*xingpage/.test(receivers_type)) {
    console.log('xing page');
    flag = 0;
}

当receivers_type = "d2845a48f91b29f9d0a6e96858f05d85xing"条件正常工作时。它只会进入第一个 if 循环。但是，当receivers_type =“d21fca8635940e97d0f8e132d806cedaxingpage”时，它会进入两种if情况。你能帮我解决这个问题吗？

Answer 1

您不需要 .* 选择器，因此您应该使用以下正则表达式

/xing$/  <-- the character $ means that the xing must be at the end of the string

所以你的代码将是:

//var receivers_type = "d2845a48f91b29f9d0a6e96858f05d85xing";
var receivers_type = "d21fca8635940e97d0f8e132d806cedaxingpage";
if (/xing$/.test(receivers_type)) {
    console.log('xing profile');
    flag = 1;
}
if (/xingpage$/.test(receivers_type)) {
    console.log('xing page');
    flag = 0;
}