ios - Swift-BLE-UART 如何从各种 View Controller 场景读取/写入？

Question

我一直在使用 Adafruit Basic-Chat 作为引用。

https://github.com/adafruit/Basic-Chat/tree/master/Basic%20Chat

我已自定义代码以与我自定义构建的北欧 BLE 模块进行通信，以实现基本的 UART 通信。写入 10 个字节，读取 10 个字节。我可以在 UartModuleViewController 中读写，但是当我创建一个新的 View Controller 并尝试使用相同的 peripheral.writeValue 时，应用程序似乎在我的第二个 ViewController 中的 peripheral.writeValue 行抛出错误。有人可以帮助我了解如何将相同的外围设备连接到各种 View Controller 场景，以便我可以类似地使用写入/读取功能吗？

//This is my write code
let bytes : [UInt8] = [ 0x1A, 0x2B, 0x3C, 0x4D ]
        let Transmitdata = NSData(bytes: bytes, length: bytes.count)
        peripheral.writeValue(Transmitdata as Data, for: txCharacteristic!, type: CBCharacteristicWriteType.withoutResponse)
        print("Data Sent",Transmitdata)

//这是我读取的代码

let ReceiveData = rxCharacteristic?.value
        if let ReceiveData = ReceiveData {
            let ReceivedNoOfBytes = ReceiveData.count
            var ReceivedByteArray = [UInt8](repeating: 0, count: ReceivedNoOfBytes)
            (ReceiveData as NSData).getBytes(&ReceivedByteArray, length: ReceivedNoOfBytes)
            print("Data Received ",ReceivedByteArray)

我想使用这两个相同的 block 来读取和写入我所有的 View Controller 吗？ (我有 10 个 View Controller ，我想在它们的所有类中使用相同的 block )我是 swift/iOS 的新手，可供引用的信息有限，所以我希望这能帮助更多像我这样的初学者。请帮忙。谢谢纳尔

0x1000d9b78 <+2408>:  uxtb   w2, w9
    0x1000d9b7c <+2412>:  uxtb   w5, w9
    0x1000d9b80 <+2416>:  mov    x6, x10
    0x1000d9b84 <+2420>:  bl     0x1000e0174               ; symbol stub for: function signature specialization <preserving fragile attribute, Arg[2] = Dead, Arg[3] = Dead> of Swift._fatalErrorMessage(Swift.StaticString, Swift.StaticString, file: Swift.StaticString, line: Swift.UInt, flags: Swift.UInt32) -> Swift.Never
    0x1000d9b88 <+2424>:  ldr    x8, [x19, #0xab8].  <- This is where it throws an error/exception/fatal error.

线程 1:EXC_BREAKPOINT(代码=1，子代码=0x10042b200)

Answer 1

我想通了。当我们想从中央类访问它时，从扫描的外围设备数组中传递连接的外围设备并将服务 uuid 引用到外围设备，并使用 segue 将其传递到我们想要的任何 View Controller 场景并将其引用到中央/主类所以当我们返回主视图 Controller 场景时它不会断开连接。谢谢大家的引用