javascript - 对象数组中前 2 个最大值

Question

我有一个像这样的对象数组

[ {"id":0,"start":0,"duration":117,"slide":4,"view":0},
  {"id":0,"start":0,"duration":12,"slide":1,"view":0},
  {"id":0,"start":0,"duration":8,"slide":3,"view":0},
  {"id":0,"start":0,"duration":7,"slide":2,"view":0}
];

我想要获取 3 个具有前 3 个持续时间值的对象。

Answer 1

您可以使用 Array#sort 对它们进行排序，降序并取前三个元素。

var array = [{ id: 0, start: 0, duration: 7, slide: 2, view: 0 }, { id: 0, start: 0, duration: 12, slide: 1, view: 0 }, { id: 0, start: 0, duration: 117, slide: 4, view: 0 }, { id: 0, start: 0, duration: 8, slide: 3, view: 0 }],
    top3duration = array.sort(function (a, b) { 
        return b.duration - a.duration;
    }).slice(0, 3);

console.log(top3duration);

.as-console-wrapper { max-height: 100% !important; top: 0; }