php - 在数组中协商数组

Question

当我执行正则表达式时

preg_match_all('~(https?://([-\w\.]+)+(:\d+)?(/([\w/_\.]*(\?\S+)?)?)?)~', $content, $turls);
print_r($turls);

我在数组中得到了一个数组。我只需要一个数组。

如何协商另一个数组中的数组

Answer 1

默认情况下 preg_match_all() 使用 PREG_PATTERN_ORDER 标志，这意味着:

Orders results so that $matches[0] is an array of full pattern matches, $matches1 is an array of strings matched by the first parenthesized subpattern, and so on.

参见 http://php.net/preg_match_all

这是示例输出:

array(
    0 => array( // Full pattern matches
       0 => 'http://www.w3.org/TR/html4/strict.dtd',
       1 => ...
    ),

    1 => array( // First parenthesized subpattern.
                // In your case it is the same as full pattern, because first
                // parenthesized subpattern includes all pattern :-)
       0 => 'http://www.w3.org/TR/html4/strict.dtd',
       1 => ...
    ),

    2 => array( // Second parenthesized subpattern.
       0 => 'www.w3.org',
       1 => ...
    ),
    ...
)

所以，作为R. Hill已回答，您需要 $matches[0] 才能访问所有匹配的网址。而作为 budinov.com指出，你应该删除外括号以避免第二个匹配重复第一个，例如:

preg_match_all('~https?://([-\w\.]+)+(:\d+)?(/([\w/_\.]*(\?\S+)?)?)?~', $content, $turls);
// where $turls[0] is what you need