javascript - Javascript 简介 - 语法

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已关闭。这个问题是 not reproducible or was caused by typos 。目前不接受答案。

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这个问题是由拼写错误或无法再重现的问题引起的。虽然类似的问题可能是 on-topic在这里，这个问题的解决方式不太可能帮助 future 的读者。

已关闭 6 年前。

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我正在尝试用 javascript 构建一个石头剪刀布游戏。这是我的代码:

  <script type="text/javascript">
    var options = ["r", "p", "s"];
    document.onkeyup = function(event) {
            console.log("event=", event);
            var userGuess = String.fromCharCode(event.which).toLowerCase();

            console.log(userGuess);

            var computerGuess = options[Math.floor(Math.random() * options.length)];

            console.log(computerGuess);

            if ((userGuess === "r") && (computerGuess === "p")) {
                alert("Paper smothers rock - You lose.");
            } else
            if ((userGuess === "r") && (computerGuess === "s")) {
                alert("Rock smashes scissors - You win!")
            } else
            if ((userGuess === "p") && (computerGuess === "s")) {
                alert("Scissors cuts paper to pieces - You lose.");
            } else if ((userGuess === "p") && (computerGuess === "r")) {
                alert("Paper smothers rock - You win");
            } else if ((userGuess === "s") && (computerGuess === "r")) {
                alert("Rock smashes scissors - You lose.");

            } else if ((userGuess === "s") && (computerGuess === "p")) {
                alert("Scissors cuts paper to pieces - You win!")
            } else if (userGuess === computerGuess) {
                alert("You tie!");
            }
            
    </script>

在控制台中时，我不断收到此错误:Uncaught SyntaxError: Unexpected end of input我已经尝试了很多事情，这很尴尬。再次请原谅我的笨蛋。任何帮助将不胜感激。

Answer 1

onkeyup 功能应该关闭。

<script type="text/javascript">

var options = ["r", "p", "s"];

document.onkeyup = function(event){
//Your code here
};

</script>