javascript - 过滤对象数组，其中子项必须匹配所有条件

Question

我需要解析带有嵌入对象数组的对象数组，我知道我可以使用 .filter() 来完成。但是我需要检查嵌入数组是否至少具有多种类型的对象之一。请参阅下面的示例:

我有一个车库对象数组，其中有一个“汽车”字段，它是一个汽车数组。每辆车都是具有多种品质的物体。我需要查看哪些车库至少拥有一辆“快速”汽车和至少一辆“小型”汽车。如果这两种品质属于同一辆车也没关系。在 javascript 中实现此目的最快/最有效的方法是什么？

garageArray = [
 {
  id: 10,
  cars: [
   {id: 1, qualities: ["fast", "small"]},
   {id: 2, qualities: ["offRoad", "large"]},
   {id: 3, qualities: ["fast", "loud"]}
  ]
 },
 {
  id: 20,
  cars: [
   {id: 4, qualities: ["loud"]},
   {id: 5, qualities: ["fast", "tiny"]}
  ]
 },
 {
  id: 30,
  cars: [
   {id: 6, qualities: ["slow", "small"]},
   {id: 7, qualities: ["offRoad", "tiny"]},
   {id: 8, qualities: ["fast", "loud"]}
  ]
 }
]

结果应该是 ID 为 20 和 30 的车库。

Answer 1

这应该可以做到:

garageArray.filter(garage =>
    garage.cars.some(car => car.qualities.includes("fast")) &&
    garage.cars.some(car => car.qualities.includes("tiny"))
);

但是匹配n个属性的更通用的解决方案如下:

const garageArray = [
    {
        id: 10,
        cars: [
            { id: 1, qualities: ["fast", "small"] },
            { id: 2, qualities: ["offRoad", "large"] },
            { id: 3, qualities: ["fast", "loud"] }
        ]
    },
    {
        id: 20,
        cars: [
            { id: 4, qualities: ["loud"] },
            { id: 5, qualities: ["fast", "tiny"] }
        ]
    },
    {
        id: 30,
        cars: [
            { id: 6, qualities: ["slow", "small"] },
            { id: 7, qualities: ["offRoad", "tiny"] },
            { id: 8, qualities: ["fast", "loud"] }
        ]
    }
];

var featuresTofind = ["loud", "fast", "tiny"];

var result = garageArray.filter(function (garage) {
    var featuresFound = featuresTofind.filter(function (feature) {
        return garage.cars.some(function (car) {
            return car.qualities.includes(feature);
        });
    });
    return featuresFound.length === featuresTofind.length;
});

console.log(result);