javascript - 替换对象数组

Question

我有以下对象数组

const array = [
   { home1: "05:45", dayOfWeek: 1, away: "09:30"},
   { home1: "05:15", dayOfWeek: 2, away: "09:30"},
   { home1: "17:30", dayOfWeek: 5, away: "09:30"},
   { home1: "16:30", dayOfWeek: 7, away: "09:30"}
]

我有四个 dayOfWeek (1,2,5,7)。现在我需要使用虚拟对象推送剩余的三个(3,4,6) ({ home1: "05:30", dayOfWeek: 7,away: "09:30"})

现在逻辑部分是我不知道数组中存在哪个dayOfWeek。可能只有一个、两个、三个或空白。我每次都需要在该数组中推送 7 天。

如何做到这一点？请建议我最好的方法

谢谢!!!

Answer 1

一种选择是对数组中迄今为止包含的日期进行Set，然后从 1 迭代到 7，push 将新对象推送到数组中如果该天不包含在集合中:

const array = [
   { home1: "05:45", dayOfWeek: 1, away: "09:30"},
   { home1: "05:15", dayOfWeek: 2, away: "09:30"},
   { home1: "17:30", dayOfWeek: 5, away: "09:30"},
   { home1: "16:30", dayOfWeek: 7, away: "09:30"}
];
const dummy = { home1: "05:30", away: "09:30" };
const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));
for (let i = 1; i <= 7; i++) {
  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });
}
console.log(array);

我使用了 Set 来降低复杂性，但我想如果您只需要 7 个对象，那并不重要，您可以使用 find 而无需创建预先收集

const array = [
   { home1: "05:45", dayOfWeek: 1, away: "09:30"},
   { home1: "05:15", dayOfWeek: 2, away: "09:30"},
   { home1: "17:30", dayOfWeek: 5, away: "09:30"},
   { home1: "16:30", dayOfWeek: 7, away: "09:30"}
];
const dummy = { home1: "05:30", away: "09:30" };
for (let i = 1; i <= 7; i++) {
  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {
    array.push({ ...dummy, dayOfWeek: i });
  }
}
console.log(array);