html - 显示彼此居中并顶部对齐的前 2 个 flex 元素

Question

我正在尝试将前 2 个 block 彼此居中对齐(带有紫色边框的 block )并使所有 3 个框顶部对齐。我已经使用 display: inline-flex 实现了这一点，但是是否可以仅使用 display: flex 获得相同的结果？

Fiddle

.container {
  font-size: 0;
  box-sizing: border-box;
}

.blocks {
  display: inline-flex;
}

.blocks-left {
  align-items: center;
  width: 66%;
  vertical-align: top;
  border: 2px solid purple;
}

.blocks-right {
  width: 33%;
}

.block {
  width: 100%;
}

#block-1 {
  background: red;
  height: 100px;
}

#block-2 {
  background: blue;
  height: 200px;
}

#block-3 {
  background: green;
  height: 400px;
}

<div class="container">
  <div class="blocks blocks-left">
    <div id="block-1" class="block"></div>
    <div id="block-2" class="block"></div>
  </div>
  <div class="blocks blocks-right">
   <div id="block-3" class="block"></div>
   </div>
</div> 

Answer 1

如果你想改变blocks到block-level display: flex，你可以得到相同的结果，如果你做你的container flexbox 并将 align-self: flex-start 添加到 blocks-left 元素 - 请参见下面的演示:

.container {
  font-size: 0;
  box-sizing: border-box;
  display: flex; /* added */
}

.blocks {
  display: flex; /* now flex instead of inline-flex */
}

.blocks-left {
  align-items: center;
  align-self: flex-start; /* added */
  width: 66%;
  vertical-align: top;
  border: 2px solid purple;
}

.blocks-right {
  width: 33%;
}

.block {
  width: 100%;
}

#block-1 {
  background: red;
  height: 100px;
}

#block-2 {
  background: blue;
  height: 200px;
}

#block-3 {
  background: green;
  height: 400px;
}

<div class="container">
  <div class="blocks blocks-left">
    <div id="block-1" class="block"></div>
    <div id="block-2" class="block"></div>
  </div>
  <div class="blocks blocks-right">
   <div id="block-3" class="block"></div>
   </div>
</div>