javascript - 如果每个项目都投资了数年和数月，如何实现按对象按值(value)搜索

Question

我做了一个网站，但我无法通过多维数组/对象进行搜索(我不知道有什么区别)。

在添加年份和月份之前，我直接通过标识符 array[id][field] 访问它们

如何实现多维数组中嵌套结构的搜索

我尝试在界面中使用其他字段预先定义年份和月份。它看起来令人毛骨悚然且难以理解。

{
  "2018": {
    "Aug": {
      "1": {
        "id": 1,
        "appeal_date": "2018-08-24",
        "city_of_residence": "aaa",
        "patient_name": "John",
        "patient_age": 62,
        "coordinator": "aaa",
        "source": "aaa",
        "birth_date": "1956-06-30",
        "contact_person_name": "",
        "contact_person_role": "",
        "contact_person_phones": [
          "",
          ""
        ],
        "diagnosis": "aasasd",
        "status": "9",
        "departure_date": "2016-02-18",
        "arrival_date": "2020-01-23",
        "patient_phones": [
          "",
          ""
        ],
        "editable": true
      }
    }
  },
  "2019": {
    "Oct": {
      "65": {
        "id": 65,
        "appeal_date": "2019-10-18",
        "city_of_residence": "asfsac",
        "patient_name": "asvsas",
        "patient_age": 62,
        "coordinator": "",
        "source": "asfasfa",
        "birth_date": "1956-06-30",
        "contact_person_name": "",
        "contact_person_role": "",
        "contact_person_phones": "",
        "diagnosis": "assdbcx",
        "status": "1",
        "departure_date": "",
        "arrival_date": "",
        "patient_phones": "",
        "editable": true
      }
    },
    "Jun": {
      "64": {
        "id": 64,
        "appeal_date": "2019-06-04",
        "city_of_residence": "afsfsa",
        "patient_name": "asvac",
        "patient_age": 62,
        "coordinator": "",
        "source": "agwdawdawd",
        "birth_date": "1956-06-30",
        "contact_person_name": "",
        "contact_person_role": "",
        "contact_person_phones": "",
        "diagnosis": "agsags",
        "status": "1",
        "departure_date": "",
        "arrival_date": "",
        "patient_phones": "",
        "editable": true
      }
    }
  }
}

我需要的只是更新正确对象中的一些字段

patients [2019] ['Oct'] [65] ['diagnosis'] = 'aaaaa'

类似这样的事情，但在某个月份患者可能不正确

我想要这样的东西:

patients.nestingSearchByKey (65) ['diagnosis'] = 'aaaaa'

它们的标识符是唯一的且不重复

我为我的英语道歉

请提出任何想法

Answer 1

您可以使用Object.keys来获取对象中的键数组。

var pts = {
  "2018": {
    "Aug": {
      "1": {
        "id": 1,
        "appeal_date": "2018-08-24",
        "city_of_residence": "aaa",
        "patient_name": "John",
        "patient_age": 62,
        "coordinator": "aaa",
        "source": "aaa",
        "birth_date": "1956-06-30",
        "contact_person_name": "",
        "contact_person_role": "",
        "contact_person_phones": [
          "",
          ""
        ],
        "diagnosis": "aasasd",
        "status": "9",
        "departure_date": "2016-02-18",
        "arrival_date": "2020-01-23",
        "patient_phones": [
          "",
          ""
        ],
        "editable": true
      }
    }
  },
  "2019": {
    "Oct": {
      "65": {
        "id": 65,
        "appeal_date": "2019-10-18",
        "city_of_residence": "asfsac",
        "patient_name": "asvsas",
        "patient_age": 62,
        "coordinator": "",
        "source": "asfasfa",
        "birth_date": "1956-06-30",
        "contact_person_name": "",
        "contact_person_role": "",
        "contact_person_phones": "",
        "diagnosis": "assdbcx",
        "status": "1",
        "departure_date": "",
        "arrival_date": "",
        "patient_phones": "",
        "editable": true
      }
    },
    "Jun": {
      "64": {
        "id": 64,
        "appeal_date": "2019-06-04",
        "city_of_residence": "afsfsa",
        "patient_name": "asvac",
        "patient_age": 62,
        "coordinator": "",
        "source": "agwdawdawd",
        "birth_date": "1956-06-30",
        "contact_person_name": "",
        "contact_person_role": "",
        "contact_person_phones": "",
        "diagnosis": "agsags",
        "status": "1",
        "departure_date": "",
        "arrival_date": "",
        "patient_phones": "",
        "editable": true
      }
    }
  }
}

function search(patients, id) {
  var patient;
  const years = Object.keys(patients);
  years.forEach(year => {
    const months = Object.keys(patients[year]);
    months.forEach(month => {
      if (patients[year][month][id]) {
        patient = patients[year][month][id];
      }
    });
  });
  
  return patient;
}

const p = search(pts, 64);
if (p) {
  p['status'] = 0;
  console.log(pts);
} else {
  console.log('Not find patient with id 64');
}