javascript - 如何插入数组或值的对象并传输到新数据

Question

我有两个名为记录和联系人的数据，两者都有不同的lead_id 。如果lead_id与此对象的编号相同，则表明它们将连接或插入并转换为新的newRecords

我制作了一个示例数据来作为示例。希望您能举个例子。

"records": [
  {
    "lead_id": 95173,
    "user_id": 526,
    "first_name": "Aaron",
    "last_name": "De La Rosa",
  },
  {
    "lead_id": 95972,
    "user_id": 459,
    "first_name": "Abba",
    "last_name": "Lorenzo",
  },
  {
    "lead_id": 95974,
    "user_id": 459,
    "first_name": "Abba",
    "last_name": "Lorenzo",
  }
]

"contacts": [
  {
    "lead_id": 95173,
    "lead_contact_number_type_id": 1,
    "lead_contact_number_id": 25,
    "lead_contact_number": "+1 206-501-4581"
  },
  {
    "lead_id": 95972,
    "lead_contact_number_type_id": 1,
    "lead_contact_number_id": 26,
    "lead_contact_number": "+1 206-501-4582"
  },
  {
    "lead_id": 95974,
    "lead_contact_number_type_id": 1,
    "lead_contact_number_id": 27,
    "lead_contact_number": "+1 206-501-4583"
  },
  {
    "lead_id": 95173,
    "lead_contact_number_type_id": 1,
    "lead_contact_number_id": 28,
    "lead_contact_number": "+1 206-501-4584"
  }
]

预期输出

"newRecords": [
    {
      "lead_id": 95173,
      "user_id": 526,
      "first_name": "Aaron",
      "last_name": "De La Rosa",
      "contact_details": [
        {
          "lead_id": 95173,
          "lead_contact_number_type_id": 1,
          "lead_contact_number_id": 25,
          "lead_contact_number": "+1 206-501-4581"
        },
        {
          "lead_id": 95173,
          "lead_contact_number_type_id": 1,
          "lead_contact_number_id": 28,
          "lead_contact_number": "+1 206-501-4584"
        }
      ]
    },
    {
      "lead_id": 95972,
      "user_id": 459,
      "first_name": "Abba",
      "last_name": "Lorenzo",
      "contact_details": [
        {
          "lead_id": 95972,
          "lead_contact_number_type_id": 1,
          "lead_contact_number_id": 26,
          "lead_contact_number": "+1 206-501-4582"
        }
      ]
    },
    {
      "lead_id": 95974,
      "user_id": 459,
      "first_name": "Abba",
      "last_name": "Lorenzo",
      "contact_details": [
        {
          "lead_id": 95974,
          "lead_contact_number_type_id": 1,
          "lead_contact_number_id": 27,
          "lead_contact_number": "+1 206-501-4583"
        }
      ]
    }
]

示例代码

let newRecordsMultContacts = newRecordsMult.map(records => {
    lead_id = records.lead_id;
    numbers = contacts
    .filter(number => number.lead_id === lead_id)
    .map(number => number.lead_contact_number);
   return { ...records, lead_contact_number: numbers, lead_contact_number_id: number.lead_contact_number_id, lead_contact_number_type_id: number.lead_contact_number_type_id }; 
})

Answer 1

您可以在此处应用 map 和 filter 方法的组合。

应用 map 并添加通过匹配lead_id过滤的联系人作为每条记录的新contact_details字段。

下面的代码应该可以解决问题。

let newRecords = records.map((record) => {
  record['contact_details'] = contacts.filter((contact) => record.lead_id === contact.lead_id);
  return record;
});