javascript - 如何使用 Lodash 在 Typescript 中展平我的示例对象？

Question

我需要展平输入 json 并使用相同的键合并对象。预期对象的结构如下例所示:

{
  "error": {
     "group1": {
         "mapping":
             [{"0": "mapping1"},
              {"1": "mapping1"}],
         "other": 
             [{"0": "other0"}]
    },
    "group2": {
         "mapping": 
             [{"0": "mapping2"},
              {"1": "mapping2"}]

    }
  }
}

所以我想摆脱组并仅保留组的子代类型。输出应该是:

{
  "error": {
      "mapping":
        [{"0": "mapping1"},
         {"1": "mapping1"},
         {"0": "mapping2"},
         {"1": "mapping2"}]
      "other": 
        [{"0": "other0"}]
  }
}

我是 JavaScript 新手，这是我的代码，我相信它可以做得更好:

function flattenReport(obj) {
    var reports = Object.keys(obj.error)
        for (report in reports) {
            var pos = obj.error[reports[report]]
            var types = Object.keys(pos)
            for (type in types) {
                var pos1 = pos[types[type]]
                var elements = Object.keys(pos1)
                for (element in elements) {
                    if (types[type] in obj.error) {
                        obj.error[types[type]].push(pos1[element])
                }
                else {
                    obj.error[types[type]] = []
                    obj.error[types[type]].push(pos1[element])
                }
            }
        } 
    }
    return obj
}

我认为 Lodash 会帮助缩短这个时间

编辑:我忘记在函数末尾删除组

Answer 1

Lodash 可以简单地解决这个问题:

let x= {
  "error": {
     "group1": {
         "mapping":
             [{"0": "mapping1"},
              {"1": "mapping1"}],
         "other": 
             [{"0": "other0"}]
    },
    "group2": {
         "mapping": 
             [{"0": "mapping2"},
              {"1": "mapping2"}]

    }
  }
}

let result = {"error":
     _.mergeWith({},..._.map(x['error'],v=>v),(o, s)=>(o||[]).concat(s))
}

console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>