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javascript - 我究竟如何从这个巨大的 JSON 对象中获取单个值?

转载 作者:行者123 更新时间:2023-11-28 14:03:50 26 4
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我需要获取的是结果 block 中的 jpg 文件“url”值。 JSON 对我来说很新......

{
"ok":"ASSEMBLY_COMPLETED",
"message":"The assembly was successfully completed.",
"assembly_id":"99b0303243fd4a2f5da38111677aca71",
"assembly_url":"http://api2.vivian.transloadit.com/assemblies/99b0303243fd4a2f5da38111677aca71",
"bytes_received":1478560,
"bytes_expected":1478560,
"client_agent":"Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_4; en-us) AppleWebKit/533.16 (KHTML, like Gecko) Version/5.0 Safari/533.16",
"client_ip":"78.105.12.58",
"client_referer":"http://gft.me/upload/",
"start_date":"2010/07/13 23:29:31 GMT",
"upload_duration":12.732,
"execution_duration":0.688,
"fields":{

},
"uploads":[
{
"id":"9543020bcb0785b4b867b0cbb057edec",
"name":"2560x1600.jpg",
"ext":"jpg",
"size":1478068,
"mime":"image/jpeg",
"type":"image",
"field":"my_file",
"url":"http://tmp.vivian.transloadit.com/upload/ed29aaebcbbfe71cbaf885da12b244a4.jpg",
"meta":{
"width":2560,
"height":1600,
"date_recorded":null,
"date_file_created":null,
"date_file_modified":"2010/07/13 23:29:44 GMT",
"title":null,
"description":null,
"location":null,
"city":null,
"state":null,
"country":null,
"country_code":null,
"keywords":null,
"aperture":null,
"exposure_compensation":null,
"exposure_mode":null,
"exposure_time":null,
"flash":null,
"focal_length":null,
"f_number":null,
"iso":null,
"light_value":null,
"metering_mode":null,
"shutter_speed":null,
"white_balance":null,
"device_name":null,
"device_vendor":null,
"device_software":null,
"latitude":null,
"longitude":null
}
}
],
"results":{
":original":[
{
"id":"9543020bcb0785b4b867b0cbb057edec",
"name":"2560x1600.jpg",
"ext":"jpg",
"size":1478068,
"mime":"image/jpeg",
"type":"image",
"field":"my_file",
"url":"http://media.thewildtimes.com.s3.amazonaws.com/95/43020bcb0785b4b867b0cbb057edec/2560x1600.jpg",
"meta":{
"width":2560,
"height":1600,
"date_recorded":null,
"date_file_created":null,
"date_file_modified":"2010/07/13 23:29:44 GMT",
"title":null,
"description":null,
"location":null,
"city":null,
"state":null,
"country":null,
"country_code":null,
"keywords":null,
"aperture":null,
"exposure_compensation":null,
"exposure_mode":null,
"exposure_time":null,
"flash":null,
"focal_length":null,
"f_number":null,
"iso":null,
"light_value":null,
"metering_mode":null,
"shutter_speed":null,
"white_balance":null,
"device_name":null,
"device_vendor":null,
"device_software":null,
"latitude":null,
"longitude":null
}
}
]
}
}

最佳答案

<variable>.results[":original"][0].url

如果“original”前面的冒号是一个意外,那么就这样做:

<variable>.results.original[0].url

关于javascript - 我究竟如何从这个巨大的 JSON 对象中获取单个值?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3242412/

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