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javascript - JQuery 动画 Z 索引?

转载 作者:行者123 更新时间:2023-11-28 13:46:00 25 4
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在我的页面中,我有不同的菜单项,它们会触发不同的相应图片。 z-index 将相应的图片切换到顶部。这是代码:

$(document).ready(function(){

var doorOpen = false;

$("a[href=#andrew]").click(function() {

if (doorOpen) { // set animation duration for door close, based on actually needed to animate the door closed or not
var duration = 1500;
} else {
var duration = 0;
}

$("#rightdoor,#leftdoor").animate(
{"marginLeft":"0px"},
{duration:duration,
complete:function() {
$('.pic2 .pic3 .pic4 .pic5').css('zIndex', 1); //puts wrong pics in back
$('.pic1').css('zIndex', 2); //brings right pic into view
$('#rightdoor').animate({ //opens doors again
marginLeft: "150px",
}, 1500);
$('#leftdoor').animate({
marginLeft: "-150px",
}, 1500);
}
}
);

doorOpen = true;


});

$("a[href=#bugz]").click(function() {

if (doorOpen) { // set animation duration for door close, based on actually needed to animate the door closed or not
var duration = 1500;
} else {
var duration = 0;
}

$("#rightdoor,#leftdoor").animate(
{"marginLeft":"0px"},
{duration:duration,
complete:function() {
$('.pic1 .pic3 .pic4 .pic5').css('zIndex', 1); //puts wrong pics in back
$('.pic2').css('zIndex', 2); //brings right pic into view
$('#rightdoor').animate({ //opens doors again
marginLeft: "150px",
}, 1500);
$('#leftdoor').animate({
marginLeft: "-150px",
}, 1500);
}
}
);

doorOpen = true;
});
});

问题是 z-index 可以工作,但似乎每个菜单项只能工作一次。如果您最初单击#andrew,它会将 pic1 带到顶部,如果您单击 #bugz,它会将 pic2 带到顶部。但是,如果您再次单击#andrew,它会在 .css(z-index) 更改之前和之后对代码进行动画处理,但不会更改 z-index 将 pic1 返回顶部。

我是 Javascript/JQuery 新手,所以如果我遗漏了一些明显的东西,请原谅我

最佳答案

您的选择器错误:$('.pic2 .pic3 .pic4 .pic5') 查找 .pic2 的后代。

您可以使用逗号而不是空格来分隔这些类,但使用 .siblings 更简单。方法替代:

$('.pic1').css('zindex',2).siblings().css('zindex',1);

关于javascript - JQuery 动画 Z 索引?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14344814/

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