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swift - 如何在 macOS 上访问 aNotification.userInfo 字典

转载 作者:行者123 更新时间:2023-11-28 13:40:56 27 4
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当用户单击他的 MAC 上的通知警报消息时,我的应用程序打开时,我试图获取警报消息的详细信息。

我在应用程序打开时收到警报没有问题。当应用程序已打开时,以下委托(delegate)可以正常工作。

func application(_ application: NSApplication,
didReceiveRemoteNotification userInfo: [String : Any])

然而,当应用程序通过单击 od 警报通知打开时,我必须从中获取 userInfo

func applicationDidFinishLaunching(_ aNotification: Notification)

我无法检索警报 userInfo在这个函数中。

let mydictionary = aNotification.userInfo
let mydesc = mydictionary!.description
os_log("aNotification.userInfon= %{public}@", log: osLog, mydesc)

os_log 的输出, 我可以在描述中看到警告消息。

aNotification.userInfon= [AnyHashable("NSApplicationLaunchIsDefaultLaunchKey"): 0, AnyHashable("NSApplicationLaunchUserNotificationKey"): <UNNotificationResponse: 0x600003ac1480; actionIdentifier: com.apple.UNNotificationDefaultActionIdentifier, notification: <UNNotification: 0x600003ac1580; date: 2019-05-08 18:26:59 +0000, request: <UNNotificationRequest: 0x6000034cd560; identifier: E6D76BF3-6643-4627-BF38-3B11B5C3F0B3, content: <UNNotificationContent: 0x600000fe0780; title: (null), subtitle: (null), body: (14) - iPhone - Tom Owen, summaryArgument: , summaryArgumentCount: 0, categoryIdentifier: , launchImageName: , threadIdentifier: , attachments: (
), badge: 0, sound: <UNNotificationSound: 0x600001ee92c0>,, trigger: <UNPushNotificationTrigger: 0x6000038fa780; contentAvailable: NO, mutableContent: NO>>>>]

我试过很多方法来访问“词典”,下面是一种方法。

if let aps = aNotification.userInfo!["aps"] as? NSDictionary {
os_log(" aNotification.userInfo ok", log: osLog)
if let alert = aps["alert"] as? NSDictionary {
os_log("alert ok", log: osLog)
if let alertMessage = alert["body"] as? String {
os_log("body ok", log: osLog)
message = alertMessage
}
}
} else {
os_log("no aNotification.userInfo!", log: osLog)
}

但是我一直收到“no aNotification.userInfo!”

我应该如何从 userInfo 访问“body: (14) - iPhone - Tom Owen” ?

最佳答案

请仔细查看日志。您必须使用 key launchUserNotificationUserInfoKey 获取用户通知。该键的值是一个 UNNotificationResponse 实例。

你得到body

func applicationDidFinishLaunching(_ notification: Notification)
if let response = notification.userInfo?[NSApplication.launchUserNotificationUserInfoKey] as? UNNotificationResponse {
let content = response.notification.request.content
let body = content.body
message = body
}
}

但是 didReceiveRemoteNotification 传递了传统的 userInfo 字典

func application(_ application: NSApplication, didReceiveRemoteNotification userInfo: [String : Any]) {
if let aps = userInfo?["aps"] as? [String:Any] { // please use Swift native types
os_log(" aNotification.userInfo ok", log: osLog)
if let alert = aps["alert"] as? [String:Any] {
os_log("alert ok", log: osLog)
if let alertMessage = alert["body"] as? String {
os_log("body ok", log: osLog)
message = alertMessage
}
}
} else {
os_log("no aNotification.userInfo!", log: osLog)
}
}

关于swift - 如何在 macOS 上访问 aNotification.userInfo 字典,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56047413/

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