swift - 防止UIButton长按重复功能

Question

以下 UILongPressGestureRecognizer 代码有效，但它会在按住按钮时重复运行 long() 按下功能。我想让它在用户按下时只运行一次。这可能吗？

override func viewDidLoad() {

    let tapGesture = UITapGestureRecognizer(target: self, action: #selector (tap))  
    let longGesture = UILongPressGestureRecognizer(target: self, action: #selector(long))  
    tapGesture.numberOfTapsRequired = 1
    shiftBtn.addGestureRecognizer(tapGesture)
    shiftBtn.addGestureRecognizer(longGesture)
}

@objc func tap() {
    print("Short Tap")
}

@objc func long() {
    print("Long press")
}

谢谢!

Answer 1

当 gesture 激活时，您应该调用 long。每当长 gesture 事件时，它就会被调用一次。

  @objc  func hitlongprass(_ sender : Any){

        guard let longPress = sender as? UILongPressGestureRecognizer else
        { return }

        if longPress.state == .began { // When gesture activated
            long()
        }
        else if longPress.state == .changed { // gesture Calls multiple times by time changed 

        }
        else if longPress.state == .ended { // When gesture end

        }
    }

   func long() {
        print("Long press")
   }

调用:

let longGesture = UILongPressGestureRecognizer(target: self, action: #selector(hitlongprass(_:)))