swift - 获取 api 调用

Question

我想将我的后端 python 与我的前端 ios swift 应用程序链接起来。我想调用 get api 电话。我尝试了堆栈溢出的所有答案:像这个:

var url : String = "http://google.com?test=toto&test2=titi"
var request : NSMutableURLRequest = NSMutableURLRequest()
request.URL = NSURL(string: url)
request.HTTPMethod = "GET"

NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue(), completionHandler:{ (response:NSURLResponse!, data: NSData!, error: NSError!) -> Void in
    var error: AutoreleasingUnsafeMutablePointer<NSError?> = nil
    let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data, options:NSJSONReadingOptions.MutableContainers, error: error) as? NSDictionary

    if (jsonResult != nil) {
        // process jsonResult
    } else {
       // couldn't load JSON, look at error
    }

但是它在第 3 行给了我一个错误，说一行中的连续声明必须用 ; 分隔

此外，我尝试了以下方法:override func viewDidLoad() { super.viewDidLoad() self.view.backgroundColor = UIColor(red: 255/255.0,green:200/255.0,blue:100/255.0,alpha:1)

    let url = URL(string:"http://127.0.0.1:5000/")!

    let urlRequest = URLRequest(url: url)
    let session = URLSession.shared
    let task = session.dataTask(with: urlRequest, completionHandler: { (data, response, error) in
       guard error == nil else {
         print("error calling GET on /todos/1")
         print(error!)
         return
       }// do stuff with response, data & error here
    })
    guard let responseData = data else{
        print("Error: did not receive data")
           return
    }

但是第11行的数据没有被识别

Answer 1

看起来您在第二个代码段(应该是最后一行)中缺少 task.resume()。

此外，这部分应该进入 completionHandler，而不是在它之外。

guard let responseData = data else{
    print("Error: did not receive data")
       return
}