javascript - array.splice 删除错误的值并保留错误的值

Question

我想要一个由没有“拒绝”作为回应的客人组成的数组。因此，牙仙子被从阵列中删除(不应该，她“接受”了邀请)， jack ·弗罗斯特留下来(不应该，他“拒绝”了邀请)。

function getAttendees(peopleInvited, responses){
    var coming=peopleInvited;
  responses.map(function(cell){
      if (cell.response=='declined') {
        coming.splice(0,1);
         }         
      });
    return coming;  
}

var people = ['Easter Bunny', 'Tooth Fairy', 'Frosty the Snowman', 
              'Jack Frost', 'Cupid', 'Father Time'];
var responses = [ 
     {name: 'Easter Bunny', response: 'declined'}, 
     {name: 'Jack Frost', response: 'declined'}, 
     {name: 'Tooth Fairy', response: 'accepted'} 
   ];

getAttendees(people, responses); 

Answer 1

首先，您需要获取传入数组中人员的索引，然后使用 splice 根据其索引删除该人员。

function getAttendees(peopleInvited, responses){
  var coming=peopleInvited;
  responses.map(function(cell){
    if (cell.response=='declined') {
      var index = coming.indexOf(cell.name);
      coming.splice(index, 1);
    }         
  });
  return coming;  
}

var people = ['Easter Bunny', 'Tooth Fairy', 'Frosty the Snowman', 
     'Jack Frost', 'Cupid', 'Father Time'];
var responses = [ 
  {name: 'Easter Bunny', response: 'declined'}, 
  {name: 'Jack Frost', response: 'declined'}, 
  {name: 'Tooth Fairy', response: 'accepted'} 
];

getAttendees(people, responses);