ios - 我如何普遍引用 self.view？

Question

我有一个可重用的 alertController 组件，该组件被引用以在整个应用程序中创建一个 alertController。我正在尝试添加模糊效果，但我无法引用 alertController 始终位于其上的 View 。

let blurEffect = UIBlurEffect(style: .light)
let blurVisualEffectView = UIVisualEffectView(effect: blurEffect)

blurVisualEffectView.frame = self.view.bounds

let vc = UIAlertController(title: title, message: message, preferredStyle: .alert)

let alertActions = (actions.map { a in UIAlertAction(title: a.display, style: .default, handler: { _ in then() ; a.handler?() }) })

for action in alertActions {
    vc.addAction(action)
    blurVisualEffectView.removeFromSuperview()
}

if actions.isEmpty {
    let action = UIAlertAction(title: "Something went wrong", style: .default) { _ in then() }
    vc.addAction(action)
}

self.view.addSubview(blurVisualEffectView)

我得到的错误是

Use of unresolved identifier 'self'

Answer 1

你需要

extension UIViewController {

    func showBluredAlert(_ actions:[Model]) {
        let blurEffect = UIBlurEffect(style: .light)
        let blurVisualEffectView = UIVisualEffectView(effect: blurEffect)
        blurVisualEffectView.frame = self.view.bounds 
        self.view.addSubview(blurVisualEffectView)

        // add the alert here

    }
}

然后在任何 vc 实例中调用它

showBluredAlert(<#[Model]#>)

---

也不要忘记这一行

self.present(vc, animated: true, completion: nil)