SwiftUI 以编程方式从可表示对象返回到 View

Question

我正在尝试在新的 swift ui 应用程序中设置二维码阅读器。

我可以用这一行加载 UIKit 二维码阅读器 View

NavigationLink(destination: QRCodeScan()){Text("扫描二维码")}

这是我的 ViewControllerRepresentable

struct QRCodeScan: UIViewControllerRepresentable {

func makeCoordinator() -> Coordinator {
    Coordinator(self)
}

func makeUIViewController(context: Context) -> ScannerViewController {
    let vc = ScannerViewController()
    vc.delegate = context.coordinator
    return vc
}

func updateUIViewController(_ vc: ScannerViewController, context: Context) {
}

class Coordinator: NSObject, QRCodeScannerDelegate {
    func codeDidFind(_ code: String) {
        print(code)
        //Go back to the last page, take 'code' with you
    }

    var parent: QRCodeScan

    init(_ parent: QRCodeScan) {
        self.parent = parent
    }
}

在“返回最后一页...”这一行，我需要以编程方式返回到将用户发送到二维码扫描仪的页面。该页面加载了一个导航后退按钮，我非常需要复制此按钮的行为以在需要时调用

感谢任何帮助/指点

蒂亚

Answer 1

struct ContentView: View {
    @State var isActive = false
    @State var code = ""
    var body: some View {
        NavigationView {
            ZStack {
                NavigationLink(destination: DetailView(isActive: $isActive, code: $code), isActive: $isActive, label: { EmptyView() })
                Button(action: {
                    self.isActive.toggle()
                }, label: {
                    Text("navigate")
                })
            }
        }
    }
}
struct DetailView: View {

    @Binding var isActive: Bool
    @Binding var code: String

    var body: some View {
        Button(action: {
            self.code = "new code"
            self.isActive.toggle()
        }) {
            Text("Back")
        }
    }
}

这可能对你有帮助，使用 NavigationLink 的 isActive 参数来回导航