php - Swift:从服务器响应中获取 HTTP 代码

Question

我在 Swift 中使用以下函数连接到服务器上的 PHP 脚本，然后处理我的请求:

func pushtoserveronclick() {
    var URL: NSURL = NSURL(string: "http://someurl.com/")!
    var request:NSMutableURLRequest = NSMutableURLRequest(URL:URL)
    request.HTTPMethod = "POST"
    var bodyData = "data=something&version=\(appVersion)"
    request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding);
    NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue())
        {
            (response, data, error) in                       
            println(response)                
    }
 }

当我运行该应用程序时，我得到以下响应:

<NSHTTPURLResponse: 0x14e53170> { URL: http://someurl.com/ } { status code: 200, headers {
Connection = "Keep-Alive";
"Content-Type" = "text/html";
Date = "Fri, 05 Dec 2014 06:23:23 GMT";
"Keep-Alive" = "timeout=2, max=100";
Server = Apache;
"Transfer-Encoding" = Identity;

我如何获取返回的状态代码，以便我可以对其进行检查并判断它是否是连接问题？

Answer 1

NSURLConnection.sendAsynchronousRequest 在类型签名中使用 NSURLResponse，但只要您通过 HTTP 连接，实例(通常)是 NSHTTPURLResponse，其中包含 statusCode。

你可以这样检查和转换它:

if let HTTPResponse = response as? NSHTTPURLResponse {
    let statusCode = HTTPResponse.statusCode
}