ios - 在 SKLabelNode 中识别触摸的问题

Question

我已经使用 Swift 编程大约四个月了，现在使用 Sprite Kit 为 IOS 构建一些简单的 Arcade 游戏。直到最近，我在识别特定节点中的触摸方面都没有遇到任何问题。在我的一个项目的主屏幕中，我添加了另一个 SKLabelNode 用于应用程序的最新添加，遵循与其他项目相同的实现布局，但这个不起作用。当点击标签时，它应该运行一个函数但甚至没有那么远，我想出了使用断点。这是所有相关代码，请看一下，我已经看了四个多小时，这让我发疯。

import SpriteKit

let twistedLabelName = "twisted"

class StartScene: SKScene {

var play1P = SKLabelNode(fontNamed: "HelveticaNeue-Thin")
var play2P = SKLabelNode(fontNamed: "HelveticaNeue-Thin")
var playTwisted = SKLabelNode(fontNamed: "HelveticaNeue-Thin")

override func didMoveToView(view: SKView) {
    initializeValues()
    self.userInteractionEnabled = true
}

func initializeValues () {
    backgroundColor = UIColor.whiteColor()


    play1P.name = "1p"
    play1P.text = "Play 1P"
    play1P.fontColor = SKColor.blackColor()
    play1P.fontSize = 40
    play1P.position = CGPoint(x: CGRectGetMidX(self.frame), y: CGRectGetHeight(self.frame) * 0.8)
    play1P.zPosition = 100

    self.addChild(play1P)


    play2P.name = "2p"
    play2P.text = "Play 2P"
    play2P.fontColor = SKColor.blackColor()
    play2P.fontSize = 40
    play2P.position = CGPoint(x: CGRectGetMidX(self.frame), y: CGRectGetHeight(self.frame) * 0.6)
    play2P.zPosition = 100

    self.addChild(play2P)

    playTwisted.text = "Twisted"
    playTwisted.fontColor = SKColor.blackColor()
    playTwisted.name = twistedLabelName
    playTwisted.fontSize = 40
    playTwisted.position = CGPoint(x: CGRectGetMidX(self.frame), y: CGRectGetHeight(self.frame) * 0.4)

    self.addChild(playTwisted)
}

override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
    for touch in touches {
        let location = touch.locationInNode(self)
        if let theName = self.nodeAtPoint(location).name {
            if theName == "1p" {
                // Some function
            }
            else if theName == "2p" {
                // Some function
            }
            else if theName == twistedLabelName {
                // This is the one that doesn't work
                // Some function
            }
        }
    }
   }
}

Answer 1

请注意，您可以扩展任何 SKNode(包括 SKLabelNode)并在子类中处理触摸。首先设置 isUserInteractionEnabled = true。例如

import SpriteKit

class MyLabelNode: SKLabelNode {
    override init() {
        super.init()
        isUserInteractionEnabled = true
    }
    required init?(coder aDecoder: NSCoder) {
        super.init(coder:  aDecoder)
        isUserInteractionEnabled = true
    }
    override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
        print( #file + #function )
    }
}